Solved on Oct 28, 2023

Calculate $\frac{a^{2}-bc}{b+c}$ given $a=4, b=-2, c=3$ . [2 marks]

STEP 1

Assumptions1. The value of $a$ is4. The value of $b$ is -3. The value of $c$ is3

STEP 2

First, we need to substitute the given values of $a$ , $b$ , and $c$ into the expression $\frac{a^{2}-b c}{b+c}$ .
$\frac{a^{2}-b c}{b+c} = \frac{4^{2}-(-2) \cdot}{-2+}$

STEP 3

Next, we calculate the numerator and the denominator separately. First, calculate the numerator $^{2}-(-2) \cdot3$ .
$^{2}-(-2) \cdot3 =16 - (-6)$

STEP 4

implify the numerator.
$16 - (-6) =16 +6 =22$

STEP 5

Now, calculate the denominator $-2+3$ .
$-2+3 =1$

STEP 6

Now that we have the numerator and the denominator, we can divide them to find the value of the expression.
$\frac{22}{1} =22$ The value of $\frac{a^{2}-b c}{b+c}$ is22.

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Calculate $\frac{a^{2}-bc}{b+c}$ given $a=4, b=-2, c=3$ . [2 marks]

STEP 1

Assumptions1. The value of $a$ is4. The value of $b$ is -3. The value of $c$ is3

STEP 2

First, we need to substitute the given values of $a$ , $b$ , and $c$ into the expression $\frac{a^{2}-b c}{b+c}$ .
$\frac{a^{2}-b c}{b+c} = \frac{4^{2}-(-2) \cdot}{-2+}$

STEP 3

Next, we calculate the numerator and the denominator separately. First, calculate the numerator $^{2}-(-2) \cdot3$ .
$^{2}-(-2) \cdot3 =16 - (-6)$

STEP 4

implify the numerator.
$16 - (-6) =16 +6 =22$

STEP 5

Now, calculate the denominator $-2+3$ .
$-2+3 =1$

STEP 6

Now that we have the numerator and the denominator, we can divide them to find the value of the expression.
$\frac{22}{1} =22$ The value of $\frac{a^{2}-b c}{b+c}$ is22.

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Calculate a2−bcb+c\frac{a^{2}-bc}{b+c}b+ca2−bc​ given a=4,b=−2,c=3a=4, b=-2, c=3a=4,b=−2,c=3. [2 marks]

STEP 1

Assumptions1. The value of aaa is4. The value of bbb is -3. The value of ccc is3

STEP 2

First, we need to substitute the given values of aaa, bbb, and ccc into the expression a2−bcb+c\frac{a^{2}-b c}{b+c}b+ca2−bc​.a2−bcb+c=42−(−2)⋅−2+\frac{a^{2}-b c}{b+c} = \frac{4^{2}-(-2) \cdot}{-2+}b+ca2−bc​=−2+42−(−2)⋅​

STEP 3

Next, we calculate the numerator and the denominator separately. First, calculate the numerator 2−(−2)⋅3^{2}-(-2) \cdot32−(−2)⋅3.2−(−2)⋅3=16−(−6)^{2}-(-2) \cdot3 =16 - (-6)2−(−2)⋅3=16−(−6)

STEP 4

implify the numerator.16−(−6)=16+6=2216 - (-6) =16 +6 =2216−(−6)=16+6=22

STEP 5

Now, calculate the denominator −2+3-2+3−2+3.−2+3=1-2+3 =1−2+3=1

STEP 6

Now that we have the numerator and the denominator, we can divide them to find the value of the expression.221=22\frac{22}{1} =22122​=22The value of a2−bcb+c\frac{a^{2}-b c}{b+c}b+ca2−bc​ is22.

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Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

Calculate $\frac{a^{2}-bc}{b+c}$ given $a=4, b=-2, c=3$ . [2 marks]

Assumptions1. The value of $a$ is4. The value of $b$ is -3. The value of $c$ is3

First, we need to substitute the given values of $a$ , $b$ , and $c$ into the expression $\frac{a^{2}-b c}{b+c}$ .
$\frac{a^{2}-b c}{b+c} = \frac{4^{2}-(-2) \cdot}{-2+}$

Next, we calculate the numerator and the denominator separately. First, calculate the numerator $^{2}-(-2) \cdot3$ .
$^{2}-(-2) \cdot3 =16 - (-6)$

implify the numerator.
$16 - (-6) =16 +6 =22$

Now, calculate the denominator $-2+3$ .
$-2+3 =1$

Now that we have the numerator and the denominator, we can divide them to find the value of the expression.
$\frac{22}{1} =22$ The value of $\frac{a^{2}-b c}{b+c}$ is22.