Fractions and Decimals

Discrete Mathematics

Differential Equations

Solved on Jan 19, 2024

Find the x-intercept of the trend line $y=-0.13x+11.2$ . Determine if the x-intercept is plausible in a real-world scenario and explain.

STEP 1

Assumptions
1. The equation of the trend line is given by $y = -0.13x + 11.2$ .
2. The $x$ -intercept occurs when $y = 0$ .

STEP 2

To find the $x$ -intercept of the trend line, we need to set $y$ to 0 and solve for $x$ .
$0 = -0.13x + 11.2$

STEP 3

Add $0.13x$ to both sides of the equation to isolate the $x$ -term on one side.
$0.13x = 11.2$

STEP 4

Divide both sides of the equation by $0.13$ to solve for $x$ .
$x = \frac{11.2}{0.13}$

STEP 5

Calculate the value of $x$ .
$x = \frac{11.2}{0.13} \approx 86.15$

STEP 6

Interpret the result in the context of a real-world situation.
The $x$ -intercept of the trend line is approximately $x = 86.15$ . In a real-world situation, whether this is possible depends on the context of the data being represented by the trend line. For example, if the trend line represents a relationship between time and temperature, an $x$ -intercept of 86.15 could represent 86.15 hours, minutes, or days, depending on the units used. If the units and context make sense, then it is possible; otherwise, it may not be a feasible real-world scenario.

Was this helpful?

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

Contact Influencer program Policy Terms