Fractions and Decimals

Discrete Mathematics

Differential Equations

Solved on Sep 28, 2023

Find the vector $-6(-30\mathbf{i}+40\mathbf{j})$ .

STEP 1

Assumptions1. The vector u is given by $-30 \mathbf{i}+40 \mathbf{j}$ . . We are asked to find $-6 u$ .

STEP 2

The operation $-6 u$ means that we should multiply each component of the vector u by -6. $-6 u = -6 (-30 \mathbf{i}+40 \mathbf{j})$

STEP 3

istribute the -6 to each component of the vector u.
$-6 u = -6 \cdot -30 \mathbf{i} -6 \cdot40 \mathbf{j}$

STEP 4

Calculate the result of the multiplication for each component.
$-6 u =180 \mathbf{i} -240 \mathbf{j}$ So, $-6 u =180 \mathbf{i} -240 \mathbf{j}$ .

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