Solved on Jan 12, 2024

Find the values of xx and yy that satisfy the system of linear equations 2x+3y=82x + 3y = 8 and x=12yx = \frac{1}{2}y.

STEP 1

Assumptions
1. We have a system of two linear equations: 2x+3y=82x + 3y = 8 x=12yx = \frac{1}{2}y
2. We need to find the values of xx and yy that satisfy both equations simultaneously.

STEP 2

First, we express xx in terms of yy using the second equation.
x=12yx = \frac{1}{2}y

STEP 3

Now, we substitute the expression for xx from the second equation into the first equation.
2(12y)+3y=82\left(\frac{1}{2}y\right) + 3y = 8

STEP 4

Simplify the equation by multiplying through.
y+3y=8y + 3y = 8

STEP 5

Combine like terms to get a single equation in yy.
4y=84y = 8

STEP 6

Divide both sides of the equation by 4 to solve for yy.
y=84y = \frac{8}{4}

STEP 7

Calculate the value of yy.
y=2y = 2

STEP 8

Now that we have the value of yy, we can substitute it back into the second equation to find xx.
x=12yx = \frac{1}{2}y

STEP 9

Substitute the value of yy into the equation.
x=12(2)x = \frac{1}{2}(2)

STEP 10

Calculate the value of xx.
x=1x = 1
The solution to the system of equations is x=1x = 1 and y=2y = 2.

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