Solved on Sep 18, 2023

Find the value of xx where the equations y=23x4y=\frac{2}{3}x-4 and y=4x+10y=-4x+10 intersect.

STEP 1

Assumptions1. The two equations given are y=3x4y=\frac{}{3} x-4 and y=4x+10y=-4 x+10. . We are looking for the value of xx where these two equations are equal.

STEP 2

Since both equations are equal to yy, we can set them equal to each other to find the value of xx.
2x4=4x+10\frac{2}{} x -4 = -4x +10

STEP 3

To solve for xx, we first need to get rid of the fractions. Multiply every term by3 to eliminate the fraction.
323x3=3x+3103 \cdot \frac{2}{3} x -3 \cdot =3 \cdot -x +3 \cdot10

STEP 4

implify the equation.
2x12=12x+302x -12 = -12x +30

STEP 5

Next, we want to isolate xx on one side of the equation. Add 12x12x to both sides of the equation.
2x+12x=12x+12x+302x +12x = -12x +12x +30

STEP 6

implify the equation.
14x=3014x =30

STEP 7

Finally, divide both sides of the equation by14 to solve for xx.
x=3014x = \frac{30}{14}

STEP 8

implify the fraction to find the value of xx.
x=157x = \frac{15}{7}For the value of x=157x = \frac{15}{7}, the two equations y=23x4y=\frac{2}{3} x-4 and y=4x+10y=-4 x+10 are equal.

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