Solved on Feb 12, 2024

Find the value of xx in the equation y12=y2xy^{12} = y^{2x}.

STEP 1

Assumptions
1. The equation is y12=y2xy^{12} = y^{2x}.
2. The variable yy is not equal to 0 or 1, as these would make the equation trivial (any value of xx would satisfy the equation if y=1y=1, and the equation would not hold for any xx if y=0y=0).
3. We are looking for the value of xx.

STEP 2

We can solve the equation by setting the exponents equal to each other, since the bases are the same and yy is not 0 or 1.
y12=y2x12=2xy^{12} = y^{2x} \Rightarrow 12 = 2x

STEP 3

Now, we can solve for xx by dividing both sides of the equation by 2.
122=2x2\frac{12}{2} = \frac{2x}{2}

STEP 4

Calculate the value of xx.
x=122=6x = \frac{12}{2} = 6
The value of xx in the equation y12=y2xy^{12} = y^{2x} is 6.

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