Solved on Jan 18, 2024

Find the composition of the functions g(t)=t3g(t) = t - 3 and f(t)=t2+5tf(t) = t^2 + 5t.

STEP 1

Assumptions
1. The function g(t)g(t) is defined as g(t)=t3g(t) = t - 3.
2. The function f(t)f(t) is defined as f(t)=t2+5tf(t) = t^2 + 5t.
3. We need to find the product of the two functions, denoted as (gf)(t)(g \cdot f)(t).

STEP 2

To find the product of two functions, we multiply them together. The product (gf)(t)(g \cdot f)(t) is found by multiplying g(t)g(t) by f(t)f(t).
(gf)(t)=g(t)f(t)(g \cdot f)(t) = g(t) \cdot f(t)

STEP 3

Substitute the expressions for g(t)g(t) and f(t)f(t) into the product.
(gf)(t)=(t3)(t2+5t)(g \cdot f)(t) = (t - 3) \cdot (t^2 + 5t)

STEP 4

Use the distributive property to multiply each term in the first polynomial by each term in the second polynomial.
(gf)(t)=tt2+t5t3t235t(g \cdot f)(t) = t \cdot t^2 + t \cdot 5t - 3 \cdot t^2 - 3 \cdot 5t

STEP 5

Perform the multiplication for each term.
(gf)(t)=t3+5t23t215t(g \cdot f)(t) = t^3 + 5t^2 - 3t^2 - 15t

STEP 6

Combine like terms.
(gf)(t)=t3+(5t23t2)15t(g \cdot f)(t) = t^3 + (5t^2 - 3t^2) - 15t

STEP 7

Simplify the expression by combining the t2t^2 terms.
(gf)(t)=t3+2t215t(g \cdot f)(t) = t^3 + 2t^2 - 15t
The product of the functions g(t)g(t) and f(t)f(t) is t3+2t215tt^3 + 2t^2 - 15t.

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