Solved on Nov 22, 2023

Simplify the product of 127\frac{12}{7} and 98\frac{9}{8} and express it in lowest terms.

STEP 1

Assumptions1. We are multiplying two fractions, 127\frac{12}{7} and 98\frac{9}{8}. . We need to simplify the result to its lowest terms.

STEP 2

To multiply two fractions, we multiply the numerators together to get the new numerator, and the denominators together to get the new denominator.
abcd=acbd\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

STEP 3

Substitute the given fractions into the formula.
12798=12978\frac{12}{7} \cdot \frac{9}{8} = \frac{12 \cdot9}{7 \cdot8}

STEP 4

Perform the multiplication in the numerator and the denominator.
12978=10856\frac{12 \cdot9}{7 \cdot8} = \frac{108}{56}

STEP 5

To simplify the fraction, we find the greatest common divisor (GCD) of the numerator and the denominator. The GCD of108 and56 is4.

STEP 6

Divide the numerator and the denominator by their GCD to reduce the fraction to its lowest terms.
10856=108/456/4\frac{108}{56} = \frac{108/4}{56/4}

STEP 7

Perform the division in the numerator and the denominator.
108/456/4=2714\frac{108/4}{56/4} = \frac{27}{14}So, the product of 127\frac{12}{7} and 9\frac{9}{} in lowest terms is 2714\frac{27}{14}.

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