Solved on Sep 30, 2023

Find the product of 8s\frac{8}{-s} and t3\frac{-t}{3}. Simplify the result.

STEP 1

Assumptions1. We are given two fractions 8s\frac{8}{-s} and t3\frac{-t}{3}. . We need to find the product of these two fractions.
3. The product of two fractions is obtained by multiplying the numerators together to get the new numerator, and multiplying the denominators together to get the new denominator.

STEP 2

We apply the rule of multiplying fractions, which is to multiply the numerators together to get the new numerator, and multiply the denominators together to get the new denominator.
8st=8ts\frac{8}{-s} \cdot \frac{-t}{} = \frac{8 \cdot -t}{-s \cdot}

STEP 3

Perform the multiplication in the numerator and the denominator.
8ts3=8t3s\frac{8 \cdot -t}{-s \cdot3} = \frac{-8t}{-3s}

STEP 4

We can simplify the fraction by removing the negative signs from both the numerator and the denominator.
8t3s=8t3s\frac{-8t}{-3s} = \frac{8t}{3s} So, the product of 8s\frac{8}{-s} and t3\frac{-t}{3} is 8t3s\frac{8t}{3s}.

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