Solved on Feb 18, 2024

Find the missing value in the solution to the linear equation 4x+y=104x + y = 10, given the point (,6)(\quad, -6).

STEP 1

Assumptions
1. We are given a linear equation in two variables: 4x+y=104x + y = 10.
2. We are given a partial solution to the equation in the form of a point with the y-coordinate of 6-6 and an unknown x-coordinate.
3. We need to find the x-coordinate that, along with the given y-coordinate, satisfies the equation.

STEP 2

We will substitute the given y-coordinate into the equation to find the corresponding x-coordinate.
4x+y=104x + y = 10
4x+(6)=104x + (-6) = 10

STEP 3

Now, we solve for xx by isolating it on one side of the equation.
4x6=104x - 6 = 10

STEP 4

Add 66 to both sides of the equation to move the constant term to the right side.
4x6+6=10+64x - 6 + 6 = 10 + 6

STEP 5

Simplify both sides of the equation.
4x=164x = 16

STEP 6

Divide both sides of the equation by 44 to solve for xx.
4x4=164\frac{4x}{4} = \frac{16}{4}

STEP 7

Calculate the value of xx.
x=4x = 4
The complete solution to the equation with the given y-coordinate of 6-6 is (4,6)(4, -6).

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