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Solved on Nov 23, 2023

Find the smallest of 1/3+0.41/3 + 0.4, 1+2.11 + 2.1, 0.20+0.310.20 + 0.31, and 6/106/10.

STEP 1

Assumptions1. We are asked to find the lowest value among the given options. . All operations are performed according to the order of operations (PEMDAS/BODMAS).

STEP 2

First, we need to calculate the value of each option.
For option A, we haveA=1+0.4A = \frac{1}{} +0.4

STEP 3

Perform the division operation first (according to the order of operations).
A=0.3333+0.A =0.3333 +0.

STEP 4

Add the two numbers to find the value of A.
A=0.3333+0.4=0.7333A =0.3333 +0.4 =0.7333

STEP 5

For option B, we haveB=1+2.1B =1 +2.1

STEP 6

Add the two numbers to find the value of B.
B=1+2.1=3.1B =1 +2.1 =3.1

STEP 7

For option C, we haveC=0.20+0.31C =0.20 +0.31

STEP 8

Add the two numbers to find the value of C.
C=0.20+0.31=0.51C =0.20 +0.31 =0.51

STEP 9

For option D, we have=6 = \frac{6}{}

STEP 10

Perform the division operation to find the value of D.
=610=0.6 = \frac{6}{10} =0.6

STEP 11

Now that we have the values of all the options, we can compare them to find the lowest value.
The values areA =0.7333B =3.C =0.51 =0.6

STEP 12

From the calculated values, we can see that the lowest value is0.51, which is option C.
So, the lowest value is option C.

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