Solved on Nov 04, 2023

Find the intersection of sets A\mathbf{A} and B\mathbf{B} given U={s,t,u,v,W,X,y,z}\mathbf{U}=\{\mathrm{s}, \mathrm{t}, \mathrm{u}, \mathrm{v}, \mathrm{W}, \mathrm{X}, \mathrm{y}, \mathrm{z}\}, A={u,v,y,z}\mathbf{A}=\{\mathrm{u}, \mathrm{v}, \mathrm{y}, \mathrm{z}\}, and B={v,w,x,y}\mathbf{B}=\{\mathrm{v}, \mathrm{w}, \mathrm{x}, \mathrm{y}\}.

STEP 1

Assumptions1. The universal set U consists of the elements {s, t, u, v, w, x, y, z} . The set A consists of the elements {u, v, y, z}
3. The set B consists of the elements {v, w, x, y}

STEP 2

The intersection of two sets, denoted as A ∩ B, is the set of elements which are in both A and B.
AB={xxA and xB}A \cap B = \{x | x \in A \text{ and } x \in B\}

STEP 3

Now, we need to find the elements that are common to both sets A and B.

STEP 4

The common elements in sets A and B are {v, y}.
So, the intersection of sets A and B is {v, y}.
AB={v,y}A \cap B = \{v, y\}The correct answer is (c) {v, y}.

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