Solved on Dec 10, 2023

Find the missing value in the equation: t+7×3(t+7)t+1=15(t+13)t+1\frac{\square}{t+7} \times \frac{3(t+7)}{t+1}=\frac{15(t+13)}{t+1}

STEP 1

Assumptions
1. We are given a fraction equation with a missing numerator represented by a square.
2. We need to find the value of the missing expression to make the equation true for all values of t t where the equation is defined (i.e., t7 t \neq -7 and t1 t \neq -1 ).

STEP 2

First, we will simplify the left side of the equation by canceling out common factors.
t+7×3(t+7)t+1=×3t+1 \frac{\square}{t+7} \times \frac{3(t+7)}{t+1} = \frac{\square \times 3}{t+1}

STEP 3

Now, the equation looks like this:
×3t+1=15(t+13)t+1 \frac{\square \times 3}{t+1} = \frac{15(t+13)}{t+1}

STEP 4

Since the denominators on both sides of the equation are the same, we can equate the numerators directly.
×3=15(t+13) \square \times 3 = 15(t+13)

STEP 5

Divide both sides of the equation by 3 to solve for the missing expression (represented by the square).
=15(t+13)3 \square = \frac{15(t+13)}{3}

STEP 6

Simplify the right side of the equation by distributing the 15 and then dividing by 3.
=5(t+13) \square = 5(t+13)

STEP 7

Further simplify the expression by distributing the 5.
=5t+65 \square = 5t + 65
The missing expression in the calculation is 5t+65 5t + 65 .

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