Solved on Mar 13, 2024

Find the error in the math operations and provide the correct solution. 42÷5,8×5=40,9×5=45,(8×5)+2=42,42÷5=8R542 \div 5, 8 \times 5=40, 9 \times 5=45, (8 \times 5)+2=42, 42 \div 5=8 R 5

STEP 1

Assumptions
1. We are performing a division operation: 42÷542 \div 5.
2. We are using long division to find the quotient and the remainder.
3. We are checking the multiplication facts to find the closest multiples of 5 to 42.
4. We are looking for an error in the given mathematical statements.

STEP 2

First, let's verify the multiplication facts given:
8×5=408 \times 5 = 40 9×5=459 \times 5 = 45
These statements are correct as they are basic multiplication facts.

STEP 3

Now, let's examine the next statement:
(8×5)+2=42(8 \times 5) + 2 = 42
This statement is also correct as it follows from the first multiplication fact:
40+2=4240 + 2 = 42

STEP 4

Finally, let's look at the division statement:
42÷5=8R542 \div 5 = 8 R 5
This is where the error lies. When we divide 42 by 5, the remainder must be less than the divisor, which is 5 in this case.

STEP 5

To find the correct remainder, we subtract the product of the quotient and the divisor from the original number:
Remainder=42(8×5)Remainder = 42 - (8 \times 5)

STEP 6

Calculate the remainder:
Remainder=4240=2Remainder = 42 - 40 = 2

STEP 7

Now we can write the correct division statement:
42÷5=8R242 \div 5 = 8 R 2
The correct quotient is 8 and the remainder is 2, not 5.

STEP 8

Therefore, the corrected math is:
42÷58×5=409×5=45(8×5)+2=4242÷5=8R2 \begin{array}{c} 42 \div 5 \\ 8 \times 5=40 \\ 9 \times 5=45 \\ (8 \times 5)+2=42 \\ 42 \div 5=8 R 2 \end{array}

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