Solved on Oct 24, 2023

Find the equation of an absolute value function with vertex at (3,1)(-3, -1), opening upwards, and passing through (0,2)(0, 2).

STEP 1

Assumptions1. The vertex of the absolute value graph is at (-3, -1) . The graph opens upwards3. The graph has shifted to the left3 units and down one unit4. The graph goes through the point (0,)

STEP 2

The general form of an absolute value function isy=axh+ky = a|x-h| + kwhere (h, k) is the vertex of the graph, 'a' determines the direction and steepness of the graph.

STEP 3

Since the graph opens upwards, 'a' is positive. And since the graph has shifted to the left3 units and down one unit, h = -3 and k = -1. So, the function becomesy=ax+31y = a|x+3| -1

STEP 4

Now, we need to find the value of 'a'. We can do this by substituting the coordinates of the given point (0,2) into the function.
2=a0+312 = a|0+3| -1

STEP 5

olve the equation for 'a'.
2=a312 = a*3 -1

STEP 6

Rearrange the equation to isolate 'a' on one side.
a=(2+1)/3a = (2+1)/3

STEP 7

Calculate the value of 'a'.
a=3/3=1a =3/3 =1

STEP 8

Now that we have the value of 'a', we can write the equation of the function.
y=x+31y = |x+3| -1The equation of the function is y=x+31y = |x+3| -1.

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