Solved on Dec 12, 2023

Find the composite function of two given linear functions. Given f(x)=4x+14f(x) = 4x + 14 and g(x)=2x1g(x) = 2x - 1, find (fg)(x)(f \circ g)(x).

STEP 1

Assumptions
1. The function f(x)f(x) is defined as f(x)=4x+14f(x) = 4x + 14.
2. The function g(x)g(x) is defined as g(x)=2x1g(x) = 2x - 1.
3. The composition of the two functions (fg)(x)(f \circ g)(x) means f(g(x))f(g(x)).

STEP 2

To find the composition (fg)(x)(f \circ g)(x), we need to substitute g(x)g(x) into the function f(x)f(x).
(fg)(x)=f(g(x)) (f \circ g)(x) = f(g(x))

STEP 3

Now, we substitute g(x)=2x1g(x) = 2x - 1 into f(x)f(x).
(fg)(x)=f(2x1) (f \circ g)(x) = f(2x - 1)

STEP 4

Replace xx in f(x)=4x+14f(x) = 4x + 14 with (2x1)(2x - 1).
(fg)(x)=4(2x1)+14 (f \circ g)(x) = 4(2x - 1) + 14

STEP 5

Distribute the 44 across the terms inside the parentheses.
(fg)(x)=42x41+14 (f \circ g)(x) = 4 \cdot 2x - 4 \cdot 1 + 14

STEP 6

Perform the multiplication.
(fg)(x)=8x4+14 (f \circ g)(x) = 8x - 4 + 14

STEP 7

Combine the constant terms 4-4 and 1414.
(fg)(x)=8x+10 (f \circ g)(x) = 8x + 10
Thus, the composition of the functions (fg)(x)(f \circ g)(x) is 8x+108x + 10.

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