Solved on Jan 19, 2024

Evaluate the piecewise function g(x)g(x) at different values in its domain: g(4),g(2),g(0),g(3),g(4)g(-4), g(-2), g(0), g(3), g(4).

STEP 1

Assumptions
1. The function g(x)g(x) is defined piecewise with two different expressions: - x+4x+4 for 5x1-5 \leq x \leq -1 - 2x2-x for 1<x5-1 < x \leq 5
2. We need to evaluate g(x)g(x) at specific values: 4,2,0,3,4-4, -2, 0, 3, 4.

STEP 2

To evaluate g(4)g(-4), we need to determine which piece of the piecewise function to use. Since 4-4 is in the interval [5,1][-5, -1], we use the first expression.
g(4)=(4)+4g(-4) = (-4) + 4

STEP 3

Calculate the value of g(4)g(-4).
g(4)=4+4=0g(-4) = -4 + 4 = 0

STEP 4

To evaluate g(2)g(-2), we again determine which piece of the piecewise function to use. Since 2-2 is in the interval [5,1][-5, -1], we use the first expression.
g(2)=(2)+4g(-2) = (-2) + 4

STEP 5

Calculate the value of g(2)g(-2).
g(2)=2+4=2g(-2) = -2 + 4 = 2

STEP 6

To evaluate g(0)g(0), we need to determine which piece of the piecewise function to use. Since 00 is in the interval (1,5](-1, 5], we use the second expression.
g(0)=2(0)g(0) = 2 - (0)

STEP 7

Calculate the value of g(0)g(0).
g(0)=20=2g(0) = 2 - 0 = 2

STEP 8

To evaluate g(3)g(3), we determine which piece of the piecewise function to use. Since 33 is in the interval (1,5](-1, 5], we use the second expression.
g(3)=2(3)g(3) = 2 - (3)

STEP 9

Calculate the value of g(3)g(3).
g(3)=23=1g(3) = 2 - 3 = -1

STEP 10

To evaluate g(4)g(4), we determine which piece of the piecewise function to use. Since 44 is in the interval (1,5](-1, 5], we use the second expression.
g(4)=2(4)g(4) = 2 - (4)

STEP 11

Calculate the value of g(4)g(4).
g(4)=24=2g(4) = 2 - 4 = -2
The evaluated values are: g(4)=0g(2)=2g(0)=2g(3)=1g(4)=2 \begin{array}{l} g(-4)= 0 \\ g(-2)= 2 \\ g(0)= 2 \\ g(3)= -1 \\ g(4)= -2 \end{array}

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