Solved on Mar 20, 2024

Evaluate the expressions: (7)2-(7)^{2} and (2)3-(-2)^{3}.

STEP 1

Assumptions
1. We are evaluating two separate expressions.
2. The first expression is (7)2-(7)^{2}.
3. The second expression is (2)3-(-2)^{3}.
4. The exponent applies only to the number immediately preceding it, not the negative sign in front unless the negative sign is within parentheses.

STEP 2

Evaluate the first expression (7)2-(7)^{2}. The exponent applies to the number 7, not the negative sign.
(7)2=(7×7)-(7)^{2} = -(7 \times 7)

STEP 3

Calculate the value inside the parentheses.
(7×7)=(49)-(7 \times 7) = -(49)

STEP 4

Apply the negative sign to the result.
(49)=49-(49) = -49

STEP 5

Evaluate the second expression (2)3-(-2)^{3}. The exponent applies to the number -2, which is within the parentheses.
(2)3=(2×2×2)-(-2)^{3} = -(-2 \times -2 \times -2)

STEP 6

Calculate the value inside the parentheses. Remember that the product of an odd number of negative numbers is negative.
(2×2×2)=(8)-(-2 \times -2 \times -2) = -(-8)

STEP 7

Apply the negative sign to the result.
(8)=8-(-8) = 8
The evaluated expressions are:
(7)2=49(2)3=8 \begin{array}{l} -(7)^{2} = -49 \\ -(-2)^{3} = 8 \end{array}

Was this helpful?
banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ContactInfluencer programPolicyTerms
TwitterInstagramFacebookTikTokDiscord