Fractions and Decimals

Discrete Mathematics

Differential Equations

Solved on Sep 19, 2023

Evaluate the expression $\frac{m^{2}}{\sqrt{n}} + mn$ when $m=-6$ and $n=4$ .

STEP 1

Assumptions1. The value of $m$ is $-6$ . The value of $n$ is $4$

STEP 2

We need to substitute the given values of $m$ and $n$ into the expression $\frac{m^{2}}{\sqrt{n}}+m n$ .

STEP 3

Substitute $m=-6$ and $n=$ into the expression.
$\frac{(-6)^{2}}{\sqrt{}}+(-6) \cdot$

STEP 4

Calculate the square of $-6$ and the square root of $4$ .
$\frac{36}{2}+(-6) \cdot4$

STEP 5

Perform the division and multiplication operations.
$18+(-24)$

STEP 6

Finally, perform the addition operation.
$18+(-24) = -6$ So, the value of the expression $\frac{m^{2}}{\sqrt{n}}+m n$ for $m=-6$ and $n=4$ is $-6$ .

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