Solved on Feb 06, 2024

Evaluate the cube root of x6x^{6} when x=2x=2.

STEP 1

Assumptions
1. We are given the expression x63\sqrt[3]{x^{6}}.
2. We are given the value x=2x = 2.
3. We need to evaluate the expression for the given value of xx.

STEP 2

First, we need to understand the meaning of the cube root and the exponent in the expression. The cube root of a number aa, denoted as a3\sqrt[3]{a}, is a number bb such that b3=ab^3 = a. An exponent, such as x6x^6, means xx multiplied by itself 6 times.

STEP 3

Substitute the given value of xx into the expression.
x63=(2)63\sqrt[3]{x^{6}} = \sqrt[3]{(2)^{6}}

STEP 4

Calculate the exponent part of the expression first. Since x=2x = 2, we raise 2 to the power of 6.
26=2×2×2×2×2×22^6 = 2 \times 2 \times 2 \times 2 \times 2 \times 2

STEP 5

Compute the value of 262^6.
26=642^6 = 64

STEP 6

Now substitute the value of 262^6 into the cube root expression.
x63=643\sqrt[3]{x^{6}} = \sqrt[3]{64}

STEP 7

Evaluate the cube root of 64. We are looking for a number that, when multiplied by itself three times, equals 64.
643=4\sqrt[3]{64} = 4
Because 4×4×4=644 \times 4 \times 4 = 64.

STEP 8

The value of x63\sqrt[3]{x^{6}} when x=2x = 2 is 4.
x63=4\sqrt[3]{x^{6}} = 4

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