Solved on Jan 24, 2024

Evaluate 2x2^{x} for (a) x=2x=-2 and (b) x=3x=3

STEP 1

Assumptions
1. We are evaluating the expression 2x2^{x}.
2. We will evaluate it for two different values of xx: x=2x=-2 and x=3x=3.

STEP 2

First, we will evaluate 2x2^{x} for x=2x=-2. To do this, we recall that a negative exponent indicates a reciprocal.
2x=222^{x} = 2^{-2}

STEP 3

We rewrite 222^{-2} as the reciprocal of 222^{2}.
22=1222^{-2} = \frac{1}{2^{2}}

STEP 4

Now we calculate 222^{2}.
22=2×2=42^{2} = 2 \times 2 = 4

STEP 5

Substitute the value of 222^{2} into the reciprocal expression.
22=142^{-2} = \frac{1}{4}

STEP 6

Thus, 2x2^{x} evaluated at x=2x=-2 is 14\frac{1}{4}.

STEP 7

Next, we will evaluate 2x2^{x} for x=3x=3. This is a straightforward calculation since the exponent is positive.
2x=232^{x} = 2^{3}

STEP 8

Calculate 232^{3}.
23=2×2×2=82^{3} = 2 \times 2 \times 2 = 8

STEP 9

Thus, 2x2^{x} evaluated at x=3x=3 is 88.
The evaluations are: (a) For x=2x=-2, 2x=142^{x} = \frac{1}{4} (b) For x=3x=3, 2x=82^{x} = 8

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