Solved on Dec 13, 2023

Determine the periodic deposit to reach a $30,000\$ 30,000 financial goal over 5 years at a 3.5% quarterly compounded interest rate. Calculate how much of the goal comes from deposits vs. interest.
Periodic Deposit: $? every 3 months\$ ? \text{ every 3 months} Deposits: $?\$ ? Interest: $?\$ ?

STEP 1

Assumptions
1. The financial goal is 30,000.<br/>2.Theinterestrateis3.530,000.<br />2. The interest rate is 3.5% compounded quarterly.<br />3. The time for achieving the financial goal is 5 years.<br />4. The periodic deposit is made at the end of every three months.<br />5. The formula for the future value of an annuity due to regular deposits is given by: FV=P×((1+r)n1r) FV = P \times \left( \frac{(1 + r)^n - 1}{r} \right) where where FVisthefuturevalue, is the future value, Pistheperiodicdeposit, is the periodic deposit, ristheinterestrateperperiod,and is the interest rate per period, and n$ is the total number of deposits.

STEP 2

First, we need to determine the values of rr and nn for the formula. The interest rate per period (quarterly) is the annual rate divided by the number of periods per year.
r=AnnualinterestrateNumberofperiodsperyear r = \frac{Annual\, interest\, rate}{Number\, of\, periods\, per\, year}

STEP 3

Calculate the interest rate per period.
r=3.5%4=0.0354=0.00875 r = \frac{3.5\%}{4} = \frac{0.035}{4} = 0.00875

STEP 4

Determine the total number of deposits, nn, by multiplying the number of years by the number of periods per year.
n=Years×Periodsperyear n = Years \times Periods\, per\, year

STEP 5

Calculate the total number of deposits.
n=5×4=20 n = 5 \times 4 = 20

STEP 6

Now, we can use the future value of an annuity formula to solve for the periodic deposit PP.
30,000=P×((1+0.00875)2010.00875) 30,000 = P \times \left( \frac{(1 + 0.00875)^{20} - 1}{0.00875} \right)

STEP 7

Calculate the factor by which the periodic deposit will be multiplied in the formula.
((1+0.00875)2010.00875) \left( \frac{(1 + 0.00875)^{20} - 1}{0.00875} \right)

STEP 8

First, calculate (1+0.00875)20(1 + 0.00875)^{20}.
(1+0.00875)201.1916 (1 + 0.00875)^{20} \approx 1.1916

STEP 9

Subtract 1 from the result obtained in STEP_8.
1.19161=0.1916 1.1916 - 1 = 0.1916

STEP 10

Divide the result from STEP_9 by the interest rate per period.
0.19160.0087521.8971 \frac{0.1916}{0.00875} \approx 21.8971

STEP 11

Now, solve for the periodic deposit PP.
P=30,00021.8971 P = \frac{30,000}{21.8971}

STEP 12

Calculate the periodic deposit PP.
P30,00021.89711370.25 P \approx \frac{30,000}{21.8971} \approx 1370.25

STEP 13

Round up the periodic deposit to the nearest dollar as needed.
P$1371 P \approx \$1371

STEP 14

Now that we have the periodic deposit, we can calculate how much of the financial goal comes from deposits and how much comes from interest.
Totalfromdeposits=P×n Total\, from\, deposits = P \times n

STEP 15

Calculate the total from deposits.
Totalfromdeposits=$1371×20 Total\, from\, deposits = \$1371 \times 20

STEP 16

Calculate the total amount from deposits.
Totalfromdeposits=$1371×20=$27420 Total\, from\, deposits = \$1371 \times 20 = \$27420

STEP 17

To find the amount that comes from interest, subtract the total from deposits from the financial goal.
Totalfrominterest=FinancialgoalTotalfromdeposits Total\, from\, interest = Financial\, goal - Total\, from\, deposits

STEP 18

Calculate the total from interest.
Totalfrominterest=$30,000$27,420 Total\, from\, interest = \$30,000 - \$27,420

STEP 19

Calculate the total amount from interest.
Totalfrominterest=$30,000$27,420=$2580 Total\, from\, interest = \$30,000 - \$27,420 = \$2580

STEP 20

Round the total from interest to the nearest dollar as needed.
Totalfrominterest$2580 Total\, from\, interest \approx \$2580
The periodic deposit is 1371.Ofthe1371. Of the 30,000 financial goal, 27,420comesfromdepositsand27,420 comes from deposits and 2,580 comes from interest.

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