Solved on Jan 21, 2024

Find the equation where dividing both sides by 2 and then subtracting 10 is the correct order of steps. 10(x+2)=1610(x+2)=16, 2(x10)=162(x-10)=16, 2x+10=162x+10=16, 2(x+10)=162(x+10)=16.

STEP 1

Assumptions
1. We are looking for an equation that requires us to first divide both sides by 2.
2. After dividing by 2, we need to subtract 10 from both sides to solve the equation.

STEP 2

Examine the first equation 10(x+2)=1610(x+2)=16.
To solve for xx, we would first divide both sides by 10, not 2. Therefore, this equation does not meet the criteria.

STEP 3

Examine the second equation 2(x10)=162(x-10)=16.
To solve for xx, we would first divide both sides by 2, and then add 10 to both sides, not subtract. Therefore, this equation does not meet the criteria.

STEP 4

Examine the third equation 2x+10=162x+10=16.
To solve for xx, we would first subtract 10 from both sides, and then divide by 2, not the other way around. Therefore, this equation does not meet the criteria.

STEP 5

Examine the fourth equation 2(x+10)=162(x+10)=16.
To solve for xx, we would first divide both sides by 2, which would give us x+10=8x+10=8.

STEP 6

After dividing by 2, we would then subtract 10 from both sides to solve for xx.
x+1010=810x+10-10=8-10

STEP 7

This gives us x=2x=-2, which means the fourth equation 2(x+10)=162(x+10)=16 is the one that meets the criteria of first dividing both sides by 2 and then subtracting 10 from both sides.
The correct equation is 2(x+10)=162(x+10)=16.

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