Solved on Nov 07, 2023

Find the coordinates of vertex A of the triangle formed by the inequalities: x3,y2,x+y8x \geq 3, y \geq 2, x + y \leq 8.

STEP 1

Assumptions1. The given system of inequalities represents a polygon in the form of a triangle. . Each side of the triangle corresponds to the inequality with the same number.
3. The vertex A\mathbf{A} is located at the90 degree angle of the triangle.

STEP 2

The vertex A\mathbf{A} is the intersection point of the lines represented by inequalities (1) and (2). The lines are represented by the equations\begin{align*} (1) & \quad x = \\ (2) & \quad y =2 \\ \end{align*}

STEP 3

Since the lines are parallel to the axes, the intersection point A\mathbf{A} has the coordinates (3,2)(3,2).

STEP 4

However, we need to ensure that this point also satisfies the third inequality. Substitute (3,2)(3,2) into inequality (3):
x+y8x + y \leq8

STEP 5

Substitute the values of xx and yy into the inequality3+283 +2 \leq8

STEP 6

implify the left-hand side585 \leq8

STEP 7

Since 55 \leq is true, the point (3,2)(3,2) satisfies all the inequalities, so the coordinates of vertex A\mathbf{A} are (3,2)(3,2).
Hence, the coordinates of vertex A\mathbf{A} are (3,2)(3,2).

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