Solved on Jan 18, 2024

Determine if each equation is Linear, Exponential, or Neither: A) y=5x2y=-5x-2 (Linear), B) y=4x2+5y=4x^2+5 (Neither), C) y=2+3/4xy=-2+3/4x (Neither), D) y=(1.5)xy=(1.5)^x (Exponential), E) y=2(5)2y=2(5)^2 (Exponential), F) y=5(x4)2y=5(x-4)^2 (Neither), G) y=25(0.6)xy=2-5(0.6)^x (Exponential), H) y=4x+3y=\sqrt{4x+3} (Neither), M) 4=75x4=7-5x (Linear), N) y=4x+5x2y=4x+5x^2 (Neither), O) y=5(2.4)xy=5(2.4)^x (Exponential), P) y=2x4xy=2x-4^x (Neither).

STEP 1

Assumptions
1. A linear equation is of the form y=mx+by = mx + b, where mm and bb are constants.
2. An exponential equation is of the form y=abxy = a \cdot b^x, where aa and bb are constants, and bb is the base of the exponential function.
3. A quadratic equation is of the form y=ax2+bx+cy = ax^2 + bx + c, where aa, bb, and cc are constants.
4. Equations that do not fit the form of linear or exponential are considered neither.

STEP 2

Identify the type of equation A: y=5x2y=-5x-2.
This equation is in the form y=mx+by = mx + b with m=5m = -5 and b=2b = -2, which is a linear equation.

STEP 3

Identify the type of equation B: y=4x2+5y=4x^2+5.
This equation is in the form y=ax2+bx+cy = ax^2 + bx + c with a=4a = 4, b=0b = 0, and c=5c = 5, which is a quadratic equation, so it is neither linear nor exponential.

STEP 4

Identify the type of equation C: y=2+34xy=-2+\frac{3}{4}x.
This equation is in the form y=mx+by = mx + b with m=34m = \frac{3}{4} and b=2b = -2, which is a linear equation.

STEP 5

Identify the type of equation D: y=(1.5)xy=(1.5)^x.
This equation is in the form y=abxy = a \cdot b^x with a=1a = 1 and b=1.5b = 1.5, which is an exponential equation.

STEP 6

Identify the type of equation E: y=2(5)2y=2(5)^2.
This equation simplifies to y=225=50y = 2 \cdot 25 = 50, which is a constant function. Since it does not have the variable xx, it is neither linear nor exponential.

STEP 7

Identify the type of equation F: y=5(x4)2y=5(x-4)^2.
This equation is in the form y=a(xh)2+ky = a(x - h)^2 + k with a=5a = 5, h=4h = 4, and k=0k = 0, which is a quadratic equation, so it is neither linear nor exponential.

STEP 8

Identify the type of equation G: y=25(0.6)xy=2-5(0.6)^x.
This equation is in the form y=abcxy = a - b \cdot c^x with a=2a = 2, b=5b = 5, and c=0.6c = 0.6, which is an exponential equation.

STEP 9

Identify the type of equation H: y=4x+3y=\sqrt{4x+3}.
This equation is not in the form of a linear or exponential equation and involves a square root function, so it is neither.

STEP 10

Identify the type of equation M: 4=75x4=7-5x.
This equation can be rewritten in the form y=mx+by = mx + b by isolating yy: y=5x+7y = -5x + 7, which is a linear equation.

STEP 11

Identify the type of equation N: y=4x+5x2y=4x+5x^2.
This equation is in the form y=ax2+bx+cy = ax^2 + bx + c with a=5a = 5, b=4b = 4, and c=0c = 0, which is a quadratic equation, so it is neither linear nor exponential.

STEP 12

Identify the type of equation O: y=5(2.4)xy=5(2.4)^x.
This equation is in the form y=abxy = a \cdot b^x with a=5a = 5 and b=2.4b = 2.4, which is an exponential equation.

STEP 13

Identify the type of equation P: y=2x4xy=2x-4^x.
This equation is not in the form of a linear or exponential equation and involves a term with an exponential function as well as a linear term, so it is neither.
To summarize: - A: Linear - B: Neither (Quadratic) - C: Linear - D: Exponential - E: Neither (Constant) - F: Neither (Quadratic) - G: Exponential - H: Neither (Square Root) - M: Linear - N: Neither (Quadratic) - O: Exponential - P: Neither

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