Solved on Nov 28, 2023

Add or subtract measurements, enter answers with correct significant digits. $14.500 \mathrm{~mL} + 15.8 \mathrm{~mL} = \square \mathrm{mL}$ , $18.90 \mathrm{~mL} - 2.600 \mathrm{~mL} = \square \mathrm{mL}$ , $3.8 \mathrm{~mL} + 1.670 \mathrm{~mL} = \square \mathrm{mL}$ , $\square \times 10^{\square}$ $\times$ S.

STEP 1

Assumptions1. We are adding or subtracting measurements in milliliters (m). . The number of significant digits in the answer should match the least number of decimal places in the given measurements.

STEP 2

First, let's add the first set of measurements. $14.500\,m +15.8\,m = \square\,m$

STEP 3

Perform the addition.
$14.500\,m +15.8\,m =30.3\,m$

STEP 4

The answer should have one decimal place as the measurement with the least number of decimal places (15.8 mL) has one decimal place. So, the answer to the first problem is30.3 mL.

STEP 5

Next, let's subtract the second set of measurements.
$18.90\,m -2.600\,m = \square\,m$

STEP 6

Perform the subtraction.
$18.90\,m -2.600\,m =16.30\,m$

STEP 7

The answer should have three decimal places as the measurement with the least number of decimal places (2.600 mL) has three decimal places. So, the answer to the second problem is16.300 mL.

STEP 8

Finally, let's add the third set of measurements.
$3.8\,m +1.670\,m = \square\,m$

STEP 9

Perform the addition.
$3.8\,m +.670\,m =5.470\,m$

STEP 10

The answer should have one decimal place as the measurement with the least number of decimal places (3.8 mL) has one decimal place. So, the answer to the third problem is5.5 mL.
So, the answers to the problems are.30.3 mL2.16.300 mL3.5.5 mL

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STEP 1

Assumptions1. We are adding or subtracting measurements in milliliters (m). . The number of significant digits in the answer should match the least number of decimal places in the given measurements.

STEP 2

First, let's add the first set of measurements. $14.500\,m +15.8\,m = \square\,m$

STEP 3

Perform the addition.
$14.500\,m +15.8\,m =30.3\,m$

STEP 4

The answer should have one decimal place as the measurement with the least number of decimal places (15.8 mL) has one decimal place. So, the answer to the first problem is30.3 mL.

STEP 5

Next, let's subtract the second set of measurements.
$18.90\,m -2.600\,m = \square\,m$

STEP 6

Perform the subtraction.
$18.90\,m -2.600\,m =16.30\,m$

STEP 7

The answer should have three decimal places as the measurement with the least number of decimal places (2.600 mL) has three decimal places. So, the answer to the second problem is16.300 mL.

STEP 8

Finally, let's add the third set of measurements.
$3.8\,m +1.670\,m = \square\,m$

STEP 9

Perform the addition.
$3.8\,m +.670\,m =5.470\,m$

STEP 10

The answer should have one decimal place as the measurement with the least number of decimal places (3.8 mL) has one decimal place. So, the answer to the third problem is5.5 mL.
So, the answers to the problems are.30.3 mL2.16.300 mL3.5.5 mL

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STEP 1

Assumptions1. We are adding or subtracting measurements in milliliters (m). . The number of significant digits in the answer should match the least number of decimal places in the given measurements.

STEP 2

First, let's add the first set of measurements.14.500 m+15.8 m=□ m14.500\,m +15.8\,m = \square\,m14.500m+15.8m=□m

STEP 3

Perform the addition.14.500 m+15.8 m=30.3 m14.500\,m +15.8\,m =30.3\,m14.500m+15.8m=30.3m

STEP 4

The answer should have one decimal place as the measurement with the least number of decimal places (15.8 mL) has one decimal place. So, the answer to the first problem is30.3 mL.

STEP 5

Next, let's subtract the second set of measurements.18.90 m−2.600 m=□ m18.90\,m -2.600\,m = \square\,m18.90m−2.600m=□m

STEP 6

Perform the subtraction.18.90 m−2.600 m=16.30 m18.90\,m -2.600\,m =16.30\,m18.90m−2.600m=16.30m

STEP 7

The answer should have three decimal places as the measurement with the least number of decimal places (2.600 mL) has three decimal places. So, the answer to the second problem is16.300 mL.

STEP 8

Finally, let's add the third set of measurements.3.8 m+1.670 m=□ m3.8\,m +1.670\,m = \square\,m3.8m+1.670m=□m

STEP 9

Perform the addition.3.8 m+.670 m=5.470 m3.8\,m +.670\,m =5.470\,m3.8m+.670m=5.470m

STEP 10

The answer should have one decimal place as the measurement with the least number of decimal places (3.8 mL) has one decimal place. So, the answer to the third problem is5.5 mL.So, the answers to the problems are.30.3 mL2.16.300 mL3.5.5 mL

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

First, let's add the first set of measurements. $14.500\,m +15.8\,m = \square\,m$

Perform the addition.
$14.500\,m +15.8\,m =30.3\,m$

Next, let's subtract the second set of measurements.
$18.90\,m -2.600\,m = \square\,m$

Perform the subtraction.
$18.90\,m -2.600\,m =16.30\,m$

Finally, let's add the third set of measurements.
$3.8\,m +1.670\,m = \square\,m$

Perform the addition.
$3.8\,m +.670\,m =5.470\,m$

The answer should have one decimal place as the measurement with the least number of decimal places (3.8 mL) has one decimal place. So, the answer to the third problem is5.5 mL.
So, the answers to the problems are.30.3 mL2.16.300 mL3.5.5 mL