Solved on Nov 22, 2023

Solve for the unknown variable x in the given proportions. Round the solutions to two decimal places.
a. $1: 2 = 4: x$ $x=8$
b. $x: 1.2 = 3: 9$ $x=4.00$

STEP 1

Assumptions1. The given equations are in the form of a proportion, where the ratio of the first two numbers equals the ratio of the last two numbers. . We are solving for x in both equations.
3. The solutions should be rounded to two decimal places.

STEP 2

For the first equation, $12=4 x$ , we can write this as a fraction and solve for x.
$\frac{1}{2} = \frac{4}{x}$

STEP 3

To solve for x, we can cross-multiply.
$1 \cdot x =2 \cdot$

STEP 4

implify the equation to find x.
$x = \frac{2 \cdot4}{1}$

STEP 5

Calculate the value of x.
$x = \frac{8}{1} =8.00$

STEP 6

For the second equation, $x1.2=39$ , we can write this as a fraction and solve for x.
$\frac{x}{1.2} = \frac{3}{9}$

STEP 7

To solve for x, we can cross-multiply.
$x \cdot9 =1.2 \cdot3$

STEP 8

implify the equation to find x.
$x = \frac{1.2 \cdot3}{}$

STEP 9

Calculate the value of x.
$x = \frac{3.6}{9} =.40$ So, the solutions to the equations area. $x =8.00$ b. $x =.40$

Was this helpful?

Solve for the unknown variable x in the given proportions. Round the solutions to two decimal places.
a. $1: 2 = 4: x$ $x=8$
b. $x: 1.2 = 3: 9$ $x=4.00$

STEP 1

Assumptions1. The given equations are in the form of a proportion, where the ratio of the first two numbers equals the ratio of the last two numbers. . We are solving for x in both equations.
3. The solutions should be rounded to two decimal places.

STEP 2

For the first equation, $12=4 x$ , we can write this as a fraction and solve for x.
$\frac{1}{2} = \frac{4}{x}$

STEP 3

To solve for x, we can cross-multiply.
$1 \cdot x =2 \cdot$

STEP 4

implify the equation to find x.
$x = \frac{2 \cdot4}{1}$

STEP 5

Calculate the value of x.
$x = \frac{8}{1} =8.00$

STEP 6

For the second equation, $x1.2=39$ , we can write this as a fraction and solve for x.
$\frac{x}{1.2} = \frac{3}{9}$

STEP 7

To solve for x, we can cross-multiply.
$x \cdot9 =1.2 \cdot3$

STEP 8

implify the equation to find x.
$x = \frac{1.2 \cdot3}{}$

STEP 9

Calculate the value of x.
$x = \frac{3.6}{9} =.40$ So, the solutions to the equations area. $x =8.00$ b. $x =.40$

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

Solve for the unknown variable x in the given proportions. Round the solutions to two decimal places.a. 1:2=4:x1: 2 = 4: x1:2=4:x x=8 x=8 x=8b. x:1.2=3:9x: 1.2 = 3: 9x:1.2=3:9 x=4.00 x=4.00 x=4.00

STEP 1

Assumptions1. The given equations are in the form of a proportion, where the ratio of the first two numbers equals the ratio of the last two numbers. . We are solving for x in both equations.3. The solutions should be rounded to two decimal places.

STEP 2

For the first equation, 12=4x12=4 x12=4x, we can write this as a fraction and solve for x.12=4x\frac{1}{2} = \frac{4}{x}21​=x4​

STEP 3

To solve for x, we can cross-multiply.1⋅x=2⋅1 \cdot x =2 \cdot1⋅x=2⋅

STEP 4

implify the equation to find x.x=2⋅41x = \frac{2 \cdot4}{1}x=12⋅4​

STEP 5

Calculate the value of x.x=81=8.00x = \frac{8}{1} =8.00x=18​=8.00

STEP 6

For the second equation, x1.2=39x1.2=39x1.2=39, we can write this as a fraction and solve for x.x1.2=39\frac{x}{1.2} = \frac{3}{9}1.2x​=93​

STEP 7

To solve for x, we can cross-multiply.x⋅9=1.2⋅3x \cdot9 =1.2 \cdot3x⋅9=1.2⋅3

STEP 8

implify the equation to find x.x=1.2⋅3x = \frac{1.2 \cdot3}{}x=1.2⋅3​

STEP 9

Calculate the value of x.x=3.69=.40x = \frac{3.6}{9} =.40x=93.6​=.40So, the solutions to the equations area. x=8.00x =8.00x=8.00 b. x=.40x =.40x=.40

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

Solve for the unknown variable x in the given proportions. Round the solutions to two decimal places.
a. $1: 2 = 4: x$ $x=8$
b. $x: 1.2 = 3: 9$ $x=4.00$

Assumptions1. The given equations are in the form of a proportion, where the ratio of the first two numbers equals the ratio of the last two numbers. . We are solving for x in both equations.
3. The solutions should be rounded to two decimal places.

For the first equation, $12=4 x$ , we can write this as a fraction and solve for x.
$\frac{1}{2} = \frac{4}{x}$

To solve for x, we can cross-multiply.
$1 \cdot x =2 \cdot$

implify the equation to find x.
$x = \frac{2 \cdot4}{1}$

Calculate the value of x.
$x = \frac{8}{1} =8.00$

For the second equation, $x1.2=39$ , we can write this as a fraction and solve for x.
$\frac{x}{1.2} = \frac{3}{9}$

To solve for x, we can cross-multiply.
$x \cdot9 =1.2 \cdot3$

implify the equation to find x.
$x = \frac{1.2 \cdot3}{}$

Calculate the value of x.
$x = \frac{3.6}{9} =.40$ So, the solutions to the equations area. $x =8.00$ b. $x =.40$