Solved on Nov 11, 2023

A shipment of 9 tons of sugar is divided into equal-sized containers. If the shipment fills 4274 \frac{2}{7} containers, find the amount of sugar one container can hold, expressed as a simplified mixed number.

STEP 1

Assumptions1. The total weight of the sugar is9 tons. The sugar fills 474 \frac{}{7} containers3. Each container holds an equal amount of sugar

STEP 2

First, we need to convert the mixed number 4274 \frac{2}{7} to an improper fraction to make the calculation easier.
427=4×7+27=3074 \frac{2}{7} = \frac{4 \times7 +2}{7} = \frac{30}{7}

STEP 3

Now, to find the amount of sugar one container can hold, we divide the total weight of the sugar by the number of containers.
Sugarpercontainer=TotalweightofsugarNumberofcontainersSugar\, per\, container = \frac{Total\, weight\, of\, sugar}{Number\, of\, containers}

STEP 4

Plug in the values for the total weight of the sugar and the number of containers to calculate the amount of sugar per container.
Sugarpercontainer=9tons307Sugar\, per\, container = \frac{9\, tons}{\frac{30}{7}}

STEP 5

To simplify the division of fractions, we multiply by the reciprocal of the divisor.
Sugarpercontainer=9tons×730Sugar\, per\, container =9\, tons \times \frac{7}{30}

STEP 6

Calculate the amount of sugar per container.
Sugarpercontainer=9tons×30=6330tonsSugar\, per\, container =9\, tons \times \frac{}{30} = \frac{63}{30}\, tons

STEP 7

implify the fraction 6330\frac{63}{30} to its simplest form.
Sugarpercontainer=6330=2110=2110tonsSugar\, per\, container = \frac{63}{30} = \frac{21}{10} =2 \frac{1}{10}\, tonsEach container can hold 21102 \frac{1}{10} tons of sugar.

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