Solved on Dec 13, 2023

Which linear transformation from R3\mathbb{R}^{3} to R2\mathbb{R}^{2} is defined by T([x1x2x3])=[x1x2]T\left(\left[\begin{array}{l} x_{1} \\ x_{2} \\ x_{3} \end{array}\right]\right)=\left[\begin{array}{l} x_{1} \\ x_{2} \end{array}\right]?

STEP 1

Assumptions
1. A linear transformation TT from R3\mathbb{R}^3 to R2\mathbb{R}^2 should take a 3-dimensional vector as input and produce a 2-dimensional vector as output.
2. A transformation is linear if it satisfies two properties for all vectors u,vR3\mathbf{u}, \mathbf{v} \in \mathbb{R}^3 and any scalar cc: - Additivity: T(u+v)=T(u)+T(v)T(\mathbf{u} + \mathbf{v}) = T(\mathbf{u}) + T(\mathbf{v}) - Homogeneity: T(cu)=cT(u)T(c\mathbf{u}) = cT(\mathbf{u})
3. The transformation should not include any operations that violate linearity, such as squaring a variable, multiplying variables together, or using variables not present in the input vector.

STEP 2

Examine the first transformation:
T([x1x2])=[x12+x2x1x2x3]T\left(\left[\begin{array}{l} x_{1} \\ x_{2} \end{array}\right]\right)=\left[\begin{array}{r} x_{1}^{2}+x_{2} \\ x_{1}-x_{2} \\ x_{3} \end{array}\right]
This transformation cannot be linear because it includes a squared term x12x_{1}^{2}, which violates the homogeneity property, and it produces a 3-dimensional vector instead of a 2-dimensional one.

STEP 3

Examine the second transformation:
T([x1x2x3])=[x1x2]T\left(\left[\begin{array}{l} x_{1} \\ x_{2} \\ x_{3} \end{array}\right]\right)=\left[\begin{array}{l} x_{1} \\ x_{2} \end{array}\right]
This transformation takes a 3-dimensional vector and produces a 2-dimensional vector by simply taking the first two components of the input vector. This operation satisfies both additivity and homogeneity, so it is a candidate for a linear transformation.

STEP 4

Examine the third transformation:
T([x1x2])=[x1+x2x3x1x2]T\left(\left[\begin{array}{l} x_{1} \\ x_{2} \end{array}\right]\right)=\left[\begin{array}{r} x_{1}+x_{2} \\ x_{3}-x_{1} \\ x_{2} \end{array}\right]
This transformation cannot be linear because it takes a 2-dimensional vector as input and produces a 3-dimensional vector as output, which does not match the required dimensions for a transformation from R3\mathbb{R}^3 to R2\mathbb{R}^2. Additionally, it includes a variable x3x_{3} that is not present in the input vector.

STEP 5

Examine the fourth transformation:
T([x1x2x3])=[x1x2x1+x2+x3]T\left(\left[\begin{array}{l} x_{1} \\ x_{2} \\ x_{3} \end{array}\right]\right)=\left[\begin{array}{r} x_{1} x_{2} \\ x_{1}+x_{2}+x_{3} \end{array}\right]
This transformation cannot be linear because it includes a product of variables x1x2x_{1} x_{2}, which violates the homogeneity property.

STEP 6

Based on the examination of all four transformations, the only transformation that satisfies the properties of a linear transformation from R3\mathbb{R}^3 to R2\mathbb{R}^2 is the second one:
T([x1x2x3])=[x1x2]T\left(\left[\begin{array}{l} x_{1} \\ x_{2} \\ x_{3} \end{array}\right]\right)=\left[\begin{array}{l} x_{1} \\ x_{2} \end{array}\right]
This is because it takes a 3-dimensional vector as input, produces a 2-dimensional vector as output, and satisfies both additivity and homogeneity properties of a linear transformation.
The correct linear transformation from R3\mathbb{R}^{3} to R2\mathbb{R}^{2} is:
T([x1x2x3])=[x1x2]T\left(\left[\begin{array}{l} x_{1} \\ x_{2} \\ x_{3} \end{array}\right]\right)=\left[\begin{array}{l} x_{1} \\ x_{2} \end{array}\right]

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