Solved on Nov 16, 2023

Perform matrix operations on AA, BB, CC, and DD matrices, such as B+DB+D and BAB-A.

STEP 1

Assumptions1. The matrices are given as followsA=[719461]B=[1295116]C=[113487]D=[14015109]A=\left[\begin{array}{cc} 7 &19 \\ 4 & -6 \\ -1 & -\end{array}\right] \quad B=\left[\begin{array}{cc} -12 &9 \\ -5 & -1 \\ 16 &\end{array}\right] \quad C=\left[\begin{array}{ccc} 1 &13 & -4 \\ & -8 &7\end{array}\right] \quad D=\left[\begin{array}{cc} -14 &0 \\ 1 & -5 \\ 10 &9\end{array}\right] . We are asked to perform the operations B+B+ and BAB-A.
3. The addition and subtraction of matrices is only possible if the matrices have the same dimensions.

STEP 2

First, we need to check if the matrices BB and $$ have the same dimensions, as we are asked to perform the operation $B+$.
Matrix BB is a ×2 \times2 matrix and matrix $$ is also a $ \times2$ matrix. Therefore, the addition is possible.

STEP 3

Now, perform the addition operation B+B+. The addition of two matrices is done element by element.
B+=[12+(14)9+05+11+(5)16+102+9]B+ = \left[\begin{array}{cc} -12+(-14) &9+0 \\ -5+1 & -1+(-5) \\ 16+10 &2+9\end{array}\right]

STEP 4

Calculate the elements of the resulting matrix.
B+=[269462611]B+ = \left[\begin{array}{cc} -26 &9 \\ -4 & -6 \\ 26 &11\end{array}\right]

STEP 5

Next, we need to check if the matrices BB and AA have the same dimensions, as we are asked to perform the operation BAB-A.
Matrix BB is a 3×23 \times2 matrix and matrix AA is also a 3×23 \times2 matrix. Therefore, the subtraction is possible.

STEP 6

Now, perform the subtraction operation BAB-A. The subtraction of two matrices is done element by element.
BA=[12919541(6)16(1)2(2)]B-A = \left[\begin{array}{cc} -12- &9-19 \\ -5-4 & -1-(-6) \\ 16-(-1) &2-(-2) \end{array}\right]

STEP 7

Calculate the elements of the resulting matrix.
BA=[191095174]B-A = \left[\begin{array}{cc} -19 & -10 \\ -9 &5 \\ 17 &4\end{array}\right]So, the results of the operations areB+=[269462611]B+ = \left[\begin{array}{cc} -26 &9 \\ -4 & -6 \\ 26 &11\end{array}\right]andBA=[191095174]B-A = \left[\begin{array}{cc} -19 & -10 \\ -9 &5 \\ 17 &4\end{array}\right]

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