Measures of Spread

Problem 301

A wireless phone store has several smart phone models and sells them at various prices. The table shows some summary statistics for the prices of the smart phones it sells. \begin{tabular}{|c|c|c|c|c|c|c|} \hline Minimum & Q1Q_{1} & Median & Q3Q_{3} & Maximum & Mean & \begin{tabular}{c} Standard \\ Deviation \end{tabular} \\ \hline 150 & 180 & 200 & 240 & 600 & 235 & 180 \\ \hline \end{tabular}
The cheapest smart phone priced at $150\$ 150 goes on sale for $75\$ 75. Describe how this new price will affect the following values:
Range increases \square IQR \square Select an answer
Median \square Mean Select an answer \square Standard Deviation \square Add Work

See Solution

Problem 302

Suppose you scored 88,72,7988,72,79, and 81 on your four exams in a mathematics course. Calculate the range and standard deviation of your exam scores. Round the mean to the nearest tenth to calculate the standard deviation.
The range of the exam scores is 16 (Simplify your answer.) The standard deviation of the exam scores is \square \square (Round to two decimal places as needed.)

See Solution

Problem 303

Find the range and standard deviation of the set of data. 8,11,8,11,11,13,158,11,8,11,11,13,15
The range is \square (Simplify your answer.)

See Solution

Problem 304

Find the range and standard deviation of the set of data. 8,11,8,11,11,13,15=8,11,8,11,11,13,15=
The range is 7 . (Simplify your answer.) The standard deviation is \square (Round the final answer to the nearest hundredth as needed. Round all intermediate values to the nearest hundredth as needed.)

See Solution

Problem 305

31,33,36,41,3431,33,36,41,34
Find the standard deviation of the data set. Round your answer to the nearest hundredth. \square pieces of candy

See Solution

Problem 306

3,2,4,73,2,4,7
Find the standard deviation of the data set. Round your answer to the nearest hundredth. \square games

See Solution

Problem 307

(4) If XX and YY are independent random variables such that Var(X)=Var(Y)=5\operatorname{Var}(X)=\operatorname{Var}(Y)=5, then Var(X2Y+7)=\operatorname{Var}(X-2 Y+7)=. (5) Consider a normally distributed data with mean

See Solution

Problem 308

Standard 15 Suppose the mean commute time among all NKU students is 27.3 minutes with a standard deviation of 9.38 minutes. Consider samples of 49 NKU students for which the sample mean is calculated. A. Fully describe the sampling distribution of the sample mean.

See Solution

Problem 309

Fill in the blank with the appropriate word or phrase.
If p^\hat{p} is the sample proportion and nn is the sample size, then p^(1p^)n\sqrt{\frac{\hat{p}(1-\hat{p})}{n}} is the (Choose one) sample proportion sample standard deviation standard error population standard deviation

See Solution

Problem 310

An auto transmission manufacturer receives ball bearings from two different suppliers. The ball bearings must have a specified diameter of 16.30 mm with a tolerance of ±0.1 mm\pm 0.1 \mathrm{~mm}. Recent shipments from the two suppliers had ball bearings with the following diameters. Complete parts (a) through (c). \begin{tabular}{llllllll} Supplier A: & 16.22 & 16.27 & 16.32 & 16.34 & 16.36 & 16.42 & 16.45 \\ Supplier B: & 16.18 & 16.21 & 16.24 & 16.34 & 16.39 & 16.43 & 16.45 \end{tabular} a. Find the mean and standard deviation for each of the two data sets
Find the mean and standard deviation for the diameters of the ball bearings from Supplier AA mean == \square s=\mathrm{s}= \square (Round to the nearest hundredth as needed.)

See Solution

Problem 311

Lisetta's new temperature lowers the standard deviation. What can we conclude about today's temperature compared to the previous 10 days?

See Solution

Problem 312

Eileen has a data set with 12 values and a standard deviation of 0. What must be true? Select all that apply.

See Solution

Problem 313

Sandy analyzes teen wages, calculates mean, median, and standard deviation, then compares original and raised by \$2/hr.

See Solution

Problem 314

Determine μx\mu_{\mathrm{x}}^{-}and σx\sigma_{\mathrm{x}}^{-}from the given parameters of the population and sample size. μ=53,σ=6,n=35\mu=53, \sigma=6, n=35 μxˉ=53σxˉ=\begin{array}{l} \mu_{\bar{x}}=53 \\ \sigma_{\bar{x}}=\square \end{array} (Round to three decimal places as needed.)

See Solution

Problem 315

2. Consider the following frequency distribution \begin{tabular}{|l|l|l|c|l|l|l|l|} \hline Class & 151915-19 & 202420-24 & 252925-29 & 303430-34 & 353935-39 & 404440-44 & 454945-49 \\ \hline Frequency & 10 & 22 & f1f_{1} & 40 & f2f_{2} & 18 & 12 \\ \hline \end{tabular}
The total frequency is 160 and the modal value is 31.0909 . Find; i) The value of f1f_{1} and f2f_{2} ii) Mode iii) Median iv) Coefficient of Quartile deviation v) Mean vi) Mean Absolute deviation vii) Standard deviation

See Solution

Problem 316

Part 1 of 4 HW Score: 32.14\%, 32.14 of 100 points Points: 5.14 of 6 Save
Listed below in order are prices in dollars for a Big Mac hamburger in the United States, Canada, Mexico, China, Japan, Russia, Switzerland, Italy, Spain, Britain, Indla, and Egypt. Such data are used to compare currency exchange rates and the costs of goods in different countries. Find the range, variance, and standard deviation for the given sample data. What do the measures of variation tell us about the prices of a Big Mac in different countries? 5.305.272.573.203.352.306.795.064.764.372.821.86\begin{array}{llllllllllll} 5.30 & 5.27 & 2.57 & 3.20 & 3.35 & 2.30 & 6.79 & 5.06 & 4.76 & 4.37 & 2.82 & 1.86 \end{array}
The range is \square dollars. (Type an integer or decimal rounded to two decimal places as needed.)

See Solution

Problem 317

Period
7. In a normal distribution, x=3x=3 and z=0.67z=0.67. This tells you that x=3x=3 is \qquad standard deviations to the \qquad (left or right) of the mean.
8. In a normal distribution, x=5x=-5 and z=3.14z=-3.14. This tells you that x=5x=-5 is \qquad mean. standard deviations to the \qquad (left or right) of the
9. The life of Sunshine DVD players is normally distributed with a mean of 4.1 years and a standard deviation of 1.3 years. A DVD player is guaranteed for three years. We are interested in the length of time a DVD player lasts. Find the z score corresponding to the guaranteed life of 3 years
10. The systolic blood pressure (given in millimeters) of males has an approximately normal distribution with mean 125 and standard deviation 14. Systolic blood pressure for males follows a normal distribution. a. Calculate the z-scores for the male systolic blood pressure 100 and 150 millimeters. b. If a male friend of yours said that he thought his systolic blood pressure was 2.5 standard deviations below the mean, but he believed his blood pressure was between 100 and 150 millimeters, what would you say to him.

See Solution

Problem 318

Hospital Emergency Waiting Times The mean of the waiting times in an emergency room is 124 minutes with a standard deviation of 8.9 minutes for people who are admitted for additional treatment. The mean waiting time for patients who are discharged after receiving treatment is 105 minutes with a standard deviation of 9.3 minutes. Which times are more variable?
Part: 0/20 / 2 \square
Part 1 of 2
Calculate the coefficient of variation. Round your answers to one decimal place.
Additional treatment CVar : \square %\%
Discharged CVar: \square \%

See Solution

Problem 319

Following are heights, in inches, for a sample of college basketball players. 8488868570757286788186788172737677878884\begin{array}{llllllllllllllllllll} 84 & 88 & 86 & 85 & 70 & 75 & 72 & 86 & 78 & 81 & 86 & 78 & 81 & 72 & 73 & 76 & 77 & 87 & 88 & 84 \end{array}
Send data to Excel Find the sample standard deviation for the heights of the basketball players. 80.4 6.0 18.0 5.8

See Solution

Problem 320

5 a) 30 Kinder der 5 c haben die Länge einer Strecke an der Tafel auf cm genau geschätzt: 98;92;66;68;74;87;65;75;91;91;94;77;60;82;92;84;95;86;74;87;95;59;77;77;64;72;85;7298 ; 92 ; 66 ; 68 ; 74 ; 87 ; 65 ; 75 ; 91 ; 91 ; 94 ; 77 ; 60 ; 82 ; 92 ; 84 ; 95 ; 86 ; 74 ; 87 ; 95 ; 59 ; 77 ; 77 ; 64 ; 72 ; 85 ; 72; 74; 84. Bestimmen Sie die Standardabweichung ss der Schätzwerte. b) Welche Länge hat die Strecke vermutlich in Wirklichkeit (zwischen ... und ...cm)? c) Bestimmen Sie, welcher Anteil der Schätzwerte weniger als eine Standardabweichung vom Mittelwert entfernt liegt.

See Solution

Problem 321

You roll a die, winning nothing if the number of spots is odd, $1\$ 1 for a 2 or a 4 , and $10\$ 10 for a 6 . Round your answers to 3 decimal places (a) Find the expected value and standard deviation of your prospective winnings. The expected value is \square , the standard deviation is \square (b) You play twice. Find the mean of your total winnings.
The mean is \square

See Solution

Problem 322

The stock prices for eight major grocery store chains last January were: $18.24$20.34$9.36$11.53$11.21$48.04$48.82$28.27\begin{array}{llllllll} \$ 18.24 & \$ 20.34 & \$ 9.36 & \$ 11.53 & \$ 11.21 & \$ 48.04 & \$ 48.82 & \$ 28.27 \end{array} Send data to Excel
Find the range, variance, and standard deviation. Round the variance to one decimal place and the standard deviation to two decimal places, if necessary.
Part 1 of 3
The range is $39.46\$ 39.46.
Part: 1/31 / 3
Part 2 of 3
The variance is \square

See Solution

Problem 323

These data are the number of junk e-mails Lena received for 9 consecutive days. 611154322259\begin{array}{lllllllll}61 & 1 & 1 & 5 & 4 & 32 & 22 & 5 & 9\end{array}
Send data to Excel
Find the range, variance, and standard deviation. Round the variance to one decimal place and the standard deviation to two decimal places, if necessary.
Part: 0/30 / 3
Part 1 of 3
The range is \square e-mails.

See Solution

Problem 324

The weights (in pounds) of nine players from a college football team are recorded as follows. 204219305291265286303253261\begin{array}{lllllllll} 204 & 219 & 305 & 291 & 265 & 286 & 303 & 253 & 261 \end{array} Send data to Excel
Find the range, variance, and standard deviation. Round the variance to one decimal place and the standard deviation to two decimal places, if necessary. Round intermediate calculations to one decimal place.
Part: 0/30 / 3
Part 1 of 3
The range is \square pounds.

See Solution

Problem 325

Assume that hybridization experiments are conducted with peas having the property that for offspring, there is a 0.75 probability that a pea has green pods. Assume that the offspring peas are randomly selected in groups of 40 . Complete parts (a) through (c) below. a. Find the mean and the standard deviation for the numbers of peas with green pods in the groups of 40 .
The value of the mean is μ=30\mu=30 peas. (Type an integer or a decimal. Do not round.) The value of the standard deviation is σ=\sigma=\square \square peas. (Round to one decimal place as needed.)

See Solution

Problem 326

Find the variance and standard deviation of this dataset: 1.00, 2.40, 3.60, 4.45, 4.50, 5.56, 6.89, 7.33, 8.99, 10.00.

See Solution

Problem 327

Find the variance and standard deviation of this dataset: 1.00, 2.40, 3.60, 4.45, 4.50, 5.56, 6.89, 7.33, 8.99, 10.00. Options: a) 4.02, 1.12 b) 4.78, 2.21 c) 5.03, 1.35 d) 8.14, 2.85.

See Solution

Problem 328

Find the zz-score for a 90-pound dog given an average weight of 84 pounds and a standard deviation of 4 pounds.

See Solution

Problem 329

Which score from the set 10,20,30,40,50,6010, 20, 30, 40, 50, 60 has a z score of 0.00? Choices: 10, 20, 30, 35, 50.

See Solution

Problem 330

Find how many standard deviations above the mean a person with a 1Q1 \mathrm{Q} of 130 scores.

See Solution

Problem 331

Calculate the mean absolute deviation of the values 4, 15, 16, 7, 5, 19. Round to the nearest hundredth if needed.

See Solution

Problem 332

Find the standard deviation of the monthly salaries (in \1000s):1000s): 8, 13, 11, 12, 6, 10$. Round to two decimal places.

See Solution

Problem 333

Calculate the absolute and relative changes in Japan's population under 15 from 1980 (18.08\%) to 2020 (12.45\%).

See Solution

Problem 334

Calculate the range of the following traveler spending data (in billions): 20.9,33.1,21.8,58.5,23.5,110.9,30.4,24.9,74.1,60.3,40.4,45.420.9, 33.1, 21.8, 58.5, 23.5, 110.9, 30.4, 24.9, 74.1, 60.3, 40.4, 45.4. Round to two decimal places.

See Solution

Problem 335

Two groups measure fall times for a ball. Find averages, percentage errors, standard deviations, and variances. Round to two decimals.

See Solution

Problem 336

Find the range for at least 75%75\% of Americans' online time using Chebyshev's theorem, with an average of 4 hours and SD of 27 min.

See Solution

Problem 337

Find the range for online time where at least 75% of Americans lie, using Chebyshev's theorem. Average: 4 hrs, SD: 27 min.

See Solution

Problem 338

Find the range, variance, and standard deviation for the data set: 23, 32, 31, 45, 25, 33, 44, 47, 37, 32, 37, 48, 47, 50, 22, 40, 30, 28, 22, 39. Range is 28. Use sample formulas.

See Solution

Problem 339

Find the range, variance, and standard deviation of the data set: 23, 32, 31, 45, 25, 33, 44, 47, 37, 32, 37, 48, 47, 50, 22, 40, 30, 28, 22, 39. Use sample formulas.

See Solution

Problem 340

Calculate the range, variance, and standard deviation of these scores: 25, 33, 24, 40, 25, 39, 17, 45, 20, 38, 36, 37, 25, 44, 29, 36, 28, 40, 36, 33.

See Solution

Problem 341

Find the range, variance, and standard deviation for the data: 25, 33, 24, 40, 25, 39, 17, 45, 20, 38, 36, 37, 25, 44, 29, 36, 28, 40, 36, 33.

See Solution

Problem 342

Find the boundaries for 95%95\% of SAT math scores, given an average of 523 and a standard deviation of 42.

See Solution

Problem 343

Calculate the range of traveler spending: 20.7, 33.2, 21.5, 58, 23.8, 110, 30.6, 24, 74, 60.8, 40.7, 45.5, 65.6. Round to two decimal places.

See Solution

Problem 344

Calculate the variance for the numbers 20.7,33.2,21.5,58,23.8,110,30.6,24,74,60.8,40.7,45.5,65.620.7, 33.2, 21.5, 58, 23.8, 110, 30.6, 24, 74, 60.8, 40.7, 45.5, 65.6. Indicate if it's sample or population variance.

See Solution

Problem 345

Find the range of the density data: 10.34, 10.58, 10.62. Average density is 10.51 g/cm³.

See Solution

Problem 346

What does a standard deviation of 13 in exam scores mean? a. Scores are within 13 points of the mean. b. Highest and lowest scores differ by 13 points. c. Scores vary by 13 points. d. Scores vary from the mean by 13 points.

See Solution

Problem 347

Question The graph below shows the graphs of several normal distributions, labeled A,BA, B, and CC, on the same axis. Determine which normal distribution has the largest standard deviation.
Select the correct answer below: A B C

See Solution

Problem 348

Find the standard deviation for the following group of data items. 6,11,11,196,11,11,19
The standard deviation is approximately \square (Round to two decimal

See Solution

Problem 349

Confidence Intervals and Hypothesis Testing Confidence interval for the population standard deviation
The following data were randomly drawn from an approximately normal population. 48,50,55,62,66,6948,50,55,62,66,69 Send data to calculator
Based on these data, find a 90%90 \% confidence interval for the pepulation standard deviation. Then give its lower limit and upper limit. Carry your intermediate computations to at least three decimal places. Round your answers to at least two decimal places. (If necessary, consult formulas.)
Lower limit: Upper limit:

See Solution

Problem 350

1. En la siguiente tabla de se muestran los años de servicio de una muestra de 100 empleados de un banco. Completa la tabla como en los ejemplos de la guía. Luego, calcula la desviación estándar y la varianza. \begin{tabular}{|c|c|} \hline Años & NN^{\circ} Empleados \\ \hline 020-2 & 40 \\ \hline 353-5 & 25 \\ \hline 686-8 & 20 \\ \hline 9119-11 & 10 \\ \hline 121412-14 & 5 \\ \hline \end{tabular}

See Solution

Problem 351

The table gives information about the times taken by 80 people to run a race.
Time taken ( tt minutes) Cumulative Frequency 50<t601550<t703150<t805250<t906650<t1007450<t11080\begin{array}{ll} 50<t \leq 60 & 15 \\ 50<t \leq 70 & 31 \\ 50<t \leq 80 & 52 \\ 50<t \leq 90 & 66 \\ 50<t \leq 100 & 74 \\ 50<t \leq 110 & 80 \end{array}
This information is shown on the cumulative frequency graph below.
Use this graph to find an estimate for the interquartile range of the times taken.

See Solution

Problem 352

The table gives information about the times taken by 80 people to run a race.
Time taken ( tt minutes) Cumulative Frequency 50<t601550<t703150<t805250<t906650<t1007450<t11080\begin{array}{ll} 50<t \leq 60 & 15 \\ 50<t \leq 70 & 31 \\ 50<t \leq 80 & 52 \\ 50<t \leq 90 & 66 \\ 50<t \leq 100 & 74 \\ 50<t \leq 110 & 80 \end{array}
This information is shown on the cumulative frequency graph below.
Use this graph to find an estimate for the interquartile range of the times taken.

See Solution

Problem 353

The table gives information about the times taken by 80 people to run a race.
Time taken ( tt minutes) Cumulative Frequency 50<t601550<t703150<t805250<t906650<t1007450<t11080\begin{array}{ll} 50<t \leq 60 & 15 \\ 50<t \leq 70 & 31 \\ 50<t \leq 80 & 52 \\ 50<t \leq 90 & 66 \\ 50<t \leq 100 & 74 \\ 50<t \leq 110 & 80 \end{array}
This information is shown on the cumulative frequency graph below.
Use this graph to find an estimate for the interquartile range of the times taken.

See Solution

Problem 354

The weekly incomes, rounded to the nearest pound, of households on a certain street in Belfast are given below: 221248251255259263264272291297374\begin{array}{lllllllllll} 221 & 248 & 251 & 255 & 259 & 263 & 264 & 272 & 291 & 297 & 374 \end{array}
Calculate the mean and standard deviation of these weekly incomes. Give your answers to 3 significant figures. (4 marks) Q Mean, xˉ=\bar{x}= \square 0 Standard deviation, σx=\sigma_{x}= \square

See Solution

Problem 355

The weekly incomes, rounded to the nearest pound, of households on a certain street in Belfast are given below: 221248251255259263264272291297374\begin{array}{lllllllllll} 221 & 248 & 251 & 255 & 259 & 263 & 264 & 272 & 291 & 297 & 374 \end{array}
Calculate the mean and standard deviation of these weekly incomes. Give your answers to 3 significant figures. (4 marks) Q Mean, xˉ=\bar{x}= \square 0 Standard deviation, σx=\sigma_{x}= \square

See Solution

Problem 356

A group of students took some tests. A teacher is analysing the average mark for each student. Each student obtained a different average mark.
For these average marks, the lower quartile is 24 , the median is 30 and the interquartile range (IQR) is 10
The three lowest average marks are 8, 10 and 15.5 and the three highest average marks are 45, 52.5 and 56
The teacher defines an outlier to be a value that is either more than 1.5×1.5 \times IQR below the lower quartile or more than 1.5×1.5 \times IQR above the upper quartile
The outliers have been determined to be 8, 52.5 and 56 A box plot for these data is shown below.
Two more students also took the tests. Their average marks, which were both less than 45 , are added to the data and the box plot redrawn.
The median and the upper quartile are the same but the lower quartile is now 26
Redraw the box plot on the grid below, ignoring any outliers. (3 marks)

See Solution

Problem 357

Smartphones: A poll agency reports that 37%37 \% of teenagers aged 121712-17 own smartphones. A random sample of 101 teenagers is drawn. Round your answers to at least four decimal places as needed.
Part: 0/60 / 6
Part 1 of 6 (a) Find the mean μp^\mu_{\hat{p}}.
The mean μp^\mu_{\hat{p}} is 0.37
Part: 1/61 / 6
Part 2 of 6
Find the standard deviation σp^\sigma_{\hat{p}}. The standard deviation σp^\sigma_{\hat{p}} is \square.

See Solution

Problem 358

A company has been monitoring their sales, and based on the history of data collected, they can provide the following probability distribution for the number of sales per week per salesperson. What is the sales per week per person standard deviation? (Round to the nearest two decimal places) \begin{tabular}{cc} \hline Number of sales per week & Probability f(x\mathrm{f}(\mathrm{x} \\ \hline 0 & 0.09 \\ 10 & 0.15 \\ 20 & 0.42 \\ 30 & 0.26 \\ 40 & 0.08 \\ \hline \end{tabular}

See Solution

Problem 359

Question 2 of 33 This les, : \quad : 1 in This (uevioni: a If a riflernan's gursight is acjusted incorrectly, he might shoot bullets consistently close to 2 leet left of the bull's-eye target. Dram a sket this show lack of precision or bias? b. Drasn a second sketch of the target it the shots are both unbiased and precise (have little variation). The riflernan's aim is not parlect, so one bullethole. a. Drawn a sketch of the target with the bullet holes consistently close to 2 feet left of the bull's-eye target. Choose the correct target below feet. A. B. c.
Does this show lack of precision or bias?

See Solution

Problem 360

Test 3 (Chapters 7 -9) om/Student/PlayerTest.aspx?testId=2643628178.centerwin=yes
A study of all the studonts at a small college showed a mean age of 20.5 and a standard deviation of 1.8 years a. Are these numbers statistics or parameters? Explain. b. Labol both numbers with their appropriate symbol (such as x,μ,s\overline{\mathrm{x}}, \mu, \mathrm{s}, or σ\sigma ). a. Choose the correct answer below. A. The numbers are statistics because they are estimates and not certain. B. The numbers are parameters because they are for all the students, not a sample. C. The numbers are statistics because they are for all the students, not a sample. D. The numbers are parameters because they are estimates and not certain. b. Choose the correct labels below. \square =20.5=20.5 \square =1.8=1.8 Assessment Details Calculator Webcam Chat Support

See Solution

Problem 361

The mean age of all 627 used cars for sale in a newspyor one Saturday last month was 7.8 years, with a stardard deviation of 7.6 years. The distribution of agns is right-skened age of the 40 cars he samples is 8.4 years and the standard deviation of those 40 cars is 5.8 years. Complete parts a through c . (type integers or occimals.) c. Are the conditions for using the CLT (Central Limit Theorem) fulfilled? A. No, because the Normal condition is not fulfilled. B. No, because the random sample/independence and Normal conditions are not fulfilled. C. No, because the random samplelindependence condition is not fulfilled. D. Yes, all the conditions for using the CLT are fulfilled.
What would be the shape of the approximate sampling distribution of a large number of means, each from a sample of 40 cars? Normal Rinht-clement

See Solution

Problem 362

3. If a random sample of 36 is obteined from a population with mean =50=50 and a standard deviation =24=24, what is the mean and standard deviation of the sampling distribution?

See Solution

Problem 363

2. In a replication of a study in which map reading skills were investigated, 20 men and 20 women completed the original map reading task and the researchers obtained the following data: \begin{tabular}{|l|l|} \hline Male map reading scores & \begin{tabular}{l} 17,20,13,12,13,11,8,17,12,15,1417,20,13,12,13,11,8,17,12,15,14, \\ 18,20,17,17,15,13,10,5,918,20,17,17,15,13,10,5,9. \end{tabular} \\ \hline Female map reading scores & \begin{tabular}{l} 12,8,10,11,4,2,11,18,17,12,13,1012,8,10,11,4,2,11,18,17,12,13,10, \\ 3,15,11,9,10,11,16,103,15,11,9,10,11,16,10. \end{tabular} \\ \hline \end{tabular}
The mean map reading score for both groups together was 12.23. a) What percentage of the male group scored above the mean score and what percentage of the femak group scored above the mean score? Show your calculations. [4 mark ] 12÷20×100=60% men 4÷20100=20% women \begin{array}{l} 12 \div 20 \times 100=60 \% \text { men } \\ 4 \div 20 * 100=20 \% \text { women } \end{array} b) Briefly explain one reason why it is important for research to be replicated. [2 mark

See Solution

Problem 364

Find the range and standard deviation of the set of diata 10,40,6,11.1810,40,6,11.18
The range is \square (Simplify your answer) The standard deviation is \square . (Round to the nearest hundredth as needed.)

See Solution

Problem 365

Determine the range and standard deviation of the prices of carnping tents shown below. $110,$58,$80,$58,$211,$250,$58,$101,$100\$ 110, \$ 58, \$ 80, \$ 58, \$ 211, \$ 250, \$ 58, \$ 101, \$ 100
The range of the prices is $\$ \square (Simplify your answer.)

See Solution

Problem 366

Find the z-scores for vacation expenses of \$ 197, \$ 277, and \$ 310, given average \$ 247 and SD \$ 60.

See Solution

Problem 367

Shannon's train fares from NYC to D.C. are: 49, 88, 119, 133, 161, 173, 272. Find the percentile ranks for \$119 and \$272, then identify the fare with a rank of about 82\%.

See Solution

Problem 368

Calculate the sum: (155151.49)2151.49+(131134.51)2134.51+(179161.03)2161.03+(125142.97)2142.97+(103124.48)2124.48+(132110.52)2110.52\frac{(155-151.49)^{2}}{151.49} + \frac{(131-134.51)^{2}}{134.51} + \frac{(179-161.03)^{2}}{161.03} + \frac{(125-142.97)^{2}}{142.97} + \frac{(103-124.48)^{2}}{124.48} + \frac{(132-110.52)^{2}}{110.52}.

See Solution

Problem 369

Use the given sample data to find Q3Q_{3}. 4952525274675555\begin{array}{llllllll} 49 & 52 & 52 & 52 & 74 & 67 & 55 & 55 \end{array}

See Solution

Problem 370

MOHAMED - 4. Box plot /document/d/10JYuvo4Tg6n74J1Q2499ujKct3GaQf2 B7qWtyadFuY/edit?pli=18tab=t.0 x plot and Histogram analysis Extensions Help
2. What is the median homework time? 4848
3. What is the median TV time? 6060
4. What is the Upper Quartile for the TV time data? 110110
5. What does the upper quartile for TV time mean?

The point seprates the max 25\% and the min_Q3 are 75\%
6. Some students didn't watch any TV. True, False, or Cannot be determ

False becouse the TV has highest students and homework has lower students
7. The TV box-and-whisker plot contains more data than the homework gra or Cannot be determined \square Q 35%35 \% af tho ctuidante enond hathioan 18 and an minutor nar niaht an hamal Desk 1

See Solution

Problem 371

Fifteen students were selected and asked how many hours each studied for the final exam in statistics. Their answers are recorded here. 2690239497710416\begin{array}{lllllllllllllll}2 & 6 & 9 & 0 & 2 & 3 & 9 & 4 & 9 & 7 & 7 & 10 & 4 & 1 & 6\end{array} Send data to Excel
Find the range, variance, and standard deviation. Round the variance to one decimal place and the standard deviation to two decimal places, if necessary.
The range is \square 10 hours.
Part: 1/31 / 3
Part 2 of 3
The variance is \square

See Solution

Problem 372

The stock prices for eight major grocery store chains last January were: \begin{tabular}{llllllll} $18.28\$ 18.28 & $20.32\$ 20.32 & $9.36\$ 9.36 & $11.55\$ 11.55 & $11.23\$ 11.23 & $48.06\$ 48.06 & $48.84\$ 48.84 & $28.23\$ 28.23 \end{tabular} Send data to Excel
Find the range, variance, and standard deviation. Round the variance to one decimal place and the standard deviation to two decimal places, if necessary.
Part: 0/30 / 3
Part 1 of 3
The range is $\$ \square .

See Solution

Problem 373

These data are the number of junk e-mails Lena received for 9 consecutive days. 591144282059\begin{array}{lllllllll} 59 & 1 & 1 & 4 & 4 & 28 & 20 & 5 & 9 \end{array} Send data to Excel
Find the range, variance, and standard deviation. Round the variance to one decimal place and the standard deviation to two decimal places, if necessary. Part: 0/30 / 3
Part 1 of 3
The range is \square e-mails.

See Solution

Problem 374

The weights (in pounds) of nine players from a college football team are recorded as follows. 208211305295267288303253261\begin{array}{lllllllll} 208 & 211 & 305 & 295 & 267 & 288 & 303 & 253 & 261 \end{array} Send data to Excel
Find the range, variance, and standard deviation. Round the variance to one decimal place and the standard deviation to two decimal places, if necessary. Round intermediate calculations to one decimal place.
Part: 0/30 / 3
Part 1 of 3
The range is \square pounds.

See Solution

Problem 375

Ten used trail bikes are randomly selected from a bike shop, and the odometer reading of each (in miles) is recorded as follows. 19021036531899782359218369223658\begin{array}{lllllllllll}1902 & 103 & 653 & 1899 & 782 & 359 & 218 & 369 & 223 & 658\end{array} Send data to Excel
Find the range, variance, and standard deviation. Round the variance to one decimal place and the standard deviation to two decimal places, if necessary. Part: 0/30 / 3
Part 1 of 3
The range is \square miles.

See Solution

Problem 376

Acme Company widget weights are normally distributed: mean 5656 oz, SD 77 oz. Use the Empirical Rule to find:
a) Range for 68%68\% weights. b) Percentage between 5656 and 7070 oz. c) Percentage between 3535 and 7777 oz.

See Solution

Problem 377

Calculate the sample standard deviation of the following musical aptitude scores: 0 (3), 1 (1), 2 (7), 3 (0), 4 (2), 5 (3). Use two decimal places.

See Solution

Problem 378

Given the altitudes for five checkpoints:
1: -55, 2: -122, 3: -184, 4: 1116, 5: 2879.
(a) What is the altitude of a hill that is 172 feet above Checkpoint 3? (b) How much lower is Checkpoint 2 than Checkpoint 4?

See Solution

Problem 379

Find the percentage of people with IQs between 55 and 145, given a mean of 100 and a standard deviation of 15.

See Solution

Problem 380

Find the range and standard deviation of the set of data. 210,213,216,219,222,225,228 b 210,213,216,219,222,225,228 \text { b }
The range is \square (Simplify your answer.) The standard deviation is \square (Round the final answer to the nearest hundredth as needed. Round all intermediate values to the nearest hundredth as needed.)

See Solution

Problem 381

The prices of the 19 top-rated all-season tires for a specific tire size, are as follows. Answer parts (a) - (c). \begin{tabular}{llllllllll} $88\$ 88 & $118\$ 118 & $97\$ 97 & $79\$ 79 & $82\$ 82 & $92\$ 92 & $94\$ 94 & $89\$ 89 & $94\$ 94 & $81\$ 81 \\ $109\$ 109 & $115\$ 115 & $103\$ 103 & $95\$ 95 & $85\$ 85 & $92\$ 92 & $75\$ 75 & $99\$ 99 & $91\$ 91 & \end{tabular} a) Determine Q2Q_{2}. Q2=\mathrm{Q}_{2}= \square b) Determine Q1Q_{1}. Q1=Q_{1}= \square c) Determine Q3Q_{3}. Q3=Q_{3}= \square

See Solution

Problem 382

The following data are from a simple random sample. 5,8,10,7,10,145, \quad 8, \quad 10, \quad 7, \quad 10, \quad 14 What is a point estimate of the population variance σ2\sigma^{2} ? A. σ^2=s2=10.6\hat{\sigma}^{2}=s^{2}=10.6. B. σ^2=s2=6\hat{\sigma}^{2}=s^{2}=6. C. σ^2=s2=9.6\hat{\sigma}^{2}=s^{2}=9.6. D. σ^2=s2=8\hat{\sigma}^{2}=s^{2}=8. E. σ^2=s2=4.5\hat{\sigma}^{2}=s^{2}=4.5.

See Solution

Problem 383

(1) Find Q1;Q2Q3Q_{1} ; Q_{2} \leqslant Q_{3} of the following sets of data a) 21,27,23,25,23,26,29,28,29,2821,27,23,25,23,26,29,28,29,28 b) 113,119,115,114,118,117,16,115,119113,119,115,114,118,117,16,115,119 c) 58,51,59,54,51,57,56,51,53,58,5258,51,59,54,51,57,56,51,53,58,52 d) 2,11,9,13,15,19,3,7,4,12,16,18,172,11,9,13,15,19,3,7,4,12,16,18,17

See Solution

Problem 384

Calculate the sample standard deviation and sample variance for the following frequency distribution of final exam scores in a statistics class. If necessary, round to one more decimal place than the largest number of decimal places given in the data. \begin{tabular}{|c|c|} \hline \multicolumn{2}{|c|}{ Final Exam Scores } \\ \hline Class & Frequency \\ \hline 415241-52 & 11 \\ \hline 536453-64 & 6 \\ \hline 657665-76 & 7 \\ \hline 778877-88 & 14 \\ \hline 8910089-100 & 9 \\ \hline \end{tabular} Copy Data
Answer Tables Keypad
How to enter your answer (opens in new window) Keyboard Shortcuts
Sample standard deviation: \square Sample variance: \square

See Solution

Problem 385

IvyLearn will automatically save any progress that you have made on the assignment should you want to begin the assig only hit "submit" when you are finished with the assignment and are ready to turn it into your instructor!
1 Fill in the Blank 5 points A package of Oreos has a mean weight of 252 grams and a standard deviation of 9 grams. Find the range of the weights of the middle 99.7%99.7 \% of Oreo packages.
The middle 99.7\% of Oreo packages range from type your answer... \square to \square type your answer... grams.

See Solution

Problem 386

A student measures sugar solution densities: 1.071.07, 1.811.81, 1.931.93, and 1.751.75 g/mL. How do her results compare to 1.751.75 g/mL?

See Solution

Problem 387

A contractor records the areas, in square feet, of a small sample of houses in a neighborhood to determine data about the neighborhood. They are: 2,400;1,750;1,900;2,500;2,250;2,1002,400 ; 1,750 ; 1,900 ; 2,500 ; 2,250 ; 2,100
Which of the following represents the numerator in the calculation of variance and standard deviation? (225)2+(425)2+(275)2+(325)2+(75)2+(75)2=423,750(225)^{2}+(-425)^{2}+(-275)^{2}+(325)^{2}+(75)^{2}+(-75)^{2}=423,750 (650)2+(150)2+(600)2+(250)2+(150)2+(300)2=980,000(650)^{2}+(-150)^{2}+(-600)^{2}+(250)^{2}+(150)^{2}+(-300)^{2}=980,000 (250)2+(400)2+(250)2+(350)2+(100)2+(50)2=420,000(250)^{2}+(-400)^{2}+(-250)^{2}+(350)^{2}+(100)^{2}+(-50)^{2}=420,000 DONE

See Solution

Problem 388

A new television show debuts amid great fanfare, and attracts 14 million viewers for the first episode. The number of viewers for subsequent episodes is shown in the table. \begin{tabular}{|c|c|} \hline Episode \# & \begin{tabular}{c} Viewers \\ (millions) \end{tabular} \\ \hline 1 & 14.0 \\ \hline 2 & 11.0 \\ \hline 3 & 8.8 \\ \hline 4 & 7.9 \\ \hline 5 & 7.2 \\ \hline 6 & 8.2 \\ \hline 7 & 7.9 \\ \hline 8 & 7.8 \\ \hline 9 & 7.6 \\ \hline \end{tabular}
Part: 0/20 / 2
Part 1 of 2 (a) Use a graphing calculator to find the correlation coefficient for these data. Round to three decimal places.
The correlation coefficient, rounded to three decimal places, is \square .

See Solution

Problem 389

The data below is a list of 120 values of Body Mass Index (BMI) data from the 1998 National Health Interview Survey on US adults. \begin{tabular}{llllllllll} 27.4 & 31.0 & 34.2 & 28.9 & 25.7 & 37.1 & 24.8 & 34.9 & 27.5 & 25.9 \\ 23.5 & 30.9 & 27.4 & 25.9 & 22.3 & 21.3 & 37.8 & 28.8 & 28.8 & 23.4 \\ 21.9 & 30.2 & 24.7 & 36.6 & 25.4 & 21.3 & 22.9 & 24.2 & 27.1 & 23.1 \\ 28.6 & 27.3 & 22.7 & 22.7 & 27.3 & 23.1 & 22.3 & 32.6 & 29.5 & 38.8 \\ 21.9 & 24.3 & 26.5 & 30.1 & 27.4 & 24.5 & 22.8 & 24.3 & 30.9 & 28.7 \\ 22.4 & 35.9 & 30.0 & 26.2 & 27.4 & 24.1 & 19.8 & 26.9 & 23.3 & 28.4 \\ 20.8 & 26.5 & 28.2 & 18.3 & 30.8 & 27.6 & 21.5 & 33.6 & 24.8 & 28.3 \\ 25.0 & 35.8 & 25.4 & 27.3 & 23.0 & 25.7 & 22.3 & 35.5 & 29.8 & 27.4 \\ 31.3 & 24.0 & 25.8 & 21.1 & 21.1 & 29.3 & 24.0 & 22.5 & 32.8 & 38.2 \\ 27.3 & 19.2 & 26.6 & 30.3 & 31.6 & 25.4 & 34.8 & 24.7 & 25.6 & 28.3 \\ 26.5 & 28.3 & 35.0 & 20.2 & 37.5 & 25.8 & 27.5 & 28.8 & 31.1 & 28.7 \\ 24.1 & 24.0 & 20.7 & 24.6 & 21.1 & 21.9 & 30.8 & 24.6 & 33.2 & 31.6 \end{tabular}
Perform the following using the data as provided:
1. An Ordered Array (Ascending order) of the data
2. Generate a grouped frequency distribution table with appropriate intervals
3. Draw a histogram for the distribution
4. Construct a Cumulative Relative Frequency table and use it to draw a i. cumulative frequency curve ii. cumulative frequency polygon iii. pie chart iv. cumulative relative frequency histogram
5. Compute the: i. Mean ii. Median iii. Variance iv. Standard deviation v. Coefficient of variation

See Solution

Problem 390

Calculate the sample standard deviation for the following data set. If necessary, round to one more decimal place than the largest number of decimal places given in the data. \begin{tabular}{|l|l|l|l|l|} \hline \multicolumn{5}{|c|}{\begin{tabular}{c} High Temperatures (in \\ of) for Wichita, Ks from \\ September \end{tabular}} \\ \hline 68 & 67 & 74 & 69 & 74 \\ \hline 84 & 75 & 65 & 89 & 83 \\ \hline 86 & 73 & 65 & 63 & 89 \\ \hline 87 & 84 & 81 & 76 & 86 \\ \hline \end{tabular} Copy Data
Answer How to enter your answer (opens in new window) Tables Keypad Keyboard Shortcuts

See Solution

Problem 391

Question 11 (1 point)
11. Given that the sum of squares for error (SSE) for an ANOVA F-test is 12,000 and there are 40 total experimental units with eight total treatments, find the mean square for error (MSE). A) 300 B) 375 C) 308 D) 400

Choose the one that best completes the statement or answers the question.

See Solution

Problem 392

Calculate the standard deviation for the data: 1 | 877868, 2 | 0323.

See Solution

Problem 393

Find the percentage of buyers who paid between \22,500and$24,500,givenameanof$22,500andstddevof$1000.Thepercentageis22,500 and \$24,500, given a mean of \$22,500 and std dev of \$1000. The percentage is \square \%$.

See Solution

Problem 394

Convert 98 to a zz-score for a normal distribution with mean 80 and standard deviation 12. z98=z_{98}=

See Solution

Problem 395

Find the percentage of buyers who paid between \$22,500 and \$24,500 using the normal distribution with mean \$22,500 and SD \$1000.

See Solution

Problem 396

Based on a survey of 836 adults, 64% favor gun registration. With a margin of error of ±3.5%\pm 3.5\%, find the range of support.

See Solution

Problem 397

Calculate the z-score for a murder rate of 29 per 100,000 residents with a mean of 4.87 and standard deviation of 3.8. Round to one decimal place.

See Solution

Problem 398

Test 10 fridge temperatures: 37.8,38.3,38.1,38.0,37.6,38.2,38.0,38.0,37.4,38.337.8, 38.3, 38.1, 38.0, 37.6, 38.2, 38.0, 38.0, 37.4, 38.3. Is it accurate (yes/no) and precise (yes/no)?

See Solution

Problem 399

Test 10 fridge temperatures: 37.8,38.3,38.1,38.0,37.6,38.2,38.0,38.0,37.4,38.337.8, 38.3, 38.1, 38.0, 37.6, 38.2, 38.0, 38.0, 37.4, 38.3. Is it accurate (yes/no) and precise (yes/no)?

See Solution

Problem 400

1. The accompanying data on flexural strength ( MPa ) for concrete beams of a certain type was introduced in Example 1.2. \begin{tabular}{rrrrrrr} 5.9 & 7.2 & 7.3 & 6.3 & 8.1 & 6.8 & 7.0 \\ 7.6 & 6.8 & 6.5 & 7.0 & 6.3 & 7.9 & 9.0 \\ 8.2 & 8.7 & 7.8 & 9.7 & 7.4 & 7.7 & 9.7 \\ 7.8 & 7.7 & 11.6 & 11.3 & 11.8 & 10.7 & \end{tabular} a. Calculate a point estimate of the mean value of strength for the conceptual population of all beams manufactured in this fashion, and state which estimator you used. Hint: Σxi=219.8\quad \Sigma x_{i}=219.8. b. Calculate a point estimate of the strength value that separates the weakest 50%50 \% of all such beams from the strongest 50%50 \%, and state which estimator you used. c. Calculate and interpret a point estimate of the population standard deviation σ\sigma. Which estimstor did you use? Hint: xi2=1860.94\quad \sum x_{i}^{2}=1860.94. d. Calculate a point estimate of the proportion of all such beams whose flexural strength exceeds 10 MPa . Hint: Think of an observation as a "success" if it exceeds 10. e. Calculate a point estimate of the population coefficient of variation σ/μ\sigma / \mu, and state which estimator you used.

See Solution
banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord