Math  /  Data & Statistics

QuestionAn auto transmission manufacturer receives ball bearings from two different suppliers. The ball bearings must have a specified diameter of 16.30 mm with a tolerance of ±0.1 mm\pm 0.1 \mathrm{~mm}. Recent shipments from the two suppliers had ball bearings with the following diameters. Complete parts (a) through (c). \begin{tabular}{llllllll} Supplier A: & 16.22 & 16.27 & 16.32 & 16.34 & 16.36 & 16.42 & 16.45 \\ Supplier B: & 16.18 & 16.21 & 16.24 & 16.34 & 16.39 & 16.43 & 16.45 \end{tabular} a. Find the mean and standard deviation for each of the two data sets
Find the mean and standard deviation for the diameters of the ball bearings from Supplier AA mean == \square s=\mathrm{s}= \square (Round to the nearest hundredth as needed.)

Studdy Solution
Calculate the standard deviation (ss):
s=0.006430.08s = \sqrt{0.00643} \approx 0.08
The mean is:
16.34 \boxed{16.34}
The standard deviation is:
0.08 \boxed{0.08}

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