Find the current value of a building with a replacement cost of \$560,000, 40 years life, and 30 years remaining. Options: \$420,000, \$140,000, \$392,000, \$560,000.
Let x be the number of roast beef sandwiches sold weekly. Cost: C(x)=510.000+0.55x. Revenue: R(x)=−0.001x2+3x. Find profit: P(x)=R(x)−C(x). Simplify P(x).
A sandwich shop has a weekly cost of \$515 and variable costs of \$0.55 per roast beef sandwich. a. Write the cost function C(x)=515.00+0.55x. b. The revenue function is R(x)=−0.001x2+3x. Write the profit function P(x)=R(x)−C(x). Simplify your answer.
Calculate your final course average using the weights: Tests (44%), Labs (15%), Homework (27%), Final Exam (14%) with grades 45%, 83%, 91%, and 56%. Record the average as a percentage accurate to two decimal places.
Monthly revenue from selling x wristwatches is R(x)=79x−0.2x2 and cost is C(x)=26x+1650. Find max revenue, profit function, and max profit. Explain differences in results.
Raina invested \$7800 and it increased by 7%. (a) Year-end amount as a decimal: Year-end amount = 1.07 × Original amount.
(b) Calculate the year-end amount in Raina's account: Year-end amount: \$
Monthly revenue from selling x wristwatches is R(x)=75x−0.2x2 and cost is C(x)=32x+1750. (a) Find x for max revenue and max revenue amount.
(b) Profit function is P(x)=R(x)−C(x).
(c) Find x for max profit and max profit amount.
(d) Explain differences in (a) and (c) and why a quadratic model works for revenue.
Monthly revenue from selling x wristwatches is R(x)=75x−0.2x2, and cost is C(x)=30x+1600. Find: (a) Wristwatches for max revenue and max revenue $.
(b) Profit function P(x)=R(x)−C(x).
(c) Wristwatches for max profit and max profit $.
(d) Explain why max revenue and profit quantities differ and why a quadratic model is suitable for revenue.