Math  /  Calculus

Question010y21+y3dxdy\int_{0}^{1} \int_{0}^{y^{2}} \sqrt{1+y^{3}} d x d y

Studdy Solution
Evaluar la integral con respecto a u u :
1312u1/2du\frac{1}{3} \int_{1}^{2} u^{1/2} \, du
La integral de u1/2 u^{1/2} es 23u3/2 \frac{2}{3} u^{3/2} . Evaluamos esto desde 1 hasta 2:
13[23u3/2]12\frac{1}{3} \left[ \frac{2}{3} u^{3/2} \right]_{1}^{2}
=1323[(2)3/2(1)3/2]= \frac{1}{3} \cdot \frac{2}{3} \left[ (2)^{3/2} - (1)^{3/2} \right]
=29[221]= \frac{2}{9} \left[ 2\sqrt{2} - 1 \right]
La solución de la integral es:
29(221)\boxed{\frac{2}{9} (2\sqrt{2} - 1)}

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