Math  /  Word Problems

QuestionCount the hydrogen atoms in the equation: 6CO2(g)+6H2O(l)C6H12O6(s)+6O2(g)6 \mathrm{CO}_{2}(g)+6 \mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(s)+6 \mathrm{O}_{2}(g).

Studdy Solution
Calculate the total number of hydrogen atoms on the right-hand side of the equation.
Since there is only one molecule of C6H126\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{}_{6} on the right-hand side of the equation, and each molecule contains12 hydrogen atoms, the total number of hydrogen atoms on the right-hand side of the equation is12.
The total number of hydrogen atoms on the right-hand side of the equation is12.

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