QuestionCount the hydrogen atoms in the equation: $6 \mathrm{CO}_{2}(g)+6 \mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(s)+6 \mathrm{O}_{2}(g)$ .

Studdy Solution

STEP 1

Assumptions1. The chemical equation is balanced, meaning the number of atoms of each element is the same on both sides of the equation. . We are only interested in the number of hydrogen atoms on the right-hand side of the equation.

STEP 2

Identify the molecules on the right-hand side of the equation that contain hydrogen atoms.The right-hand side of the equation is $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{}_{6}(s)+6 \mathrm{}_{2}(g)$ The molecule that contains hydrogen is $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{}_{6}$ .

STEP 3

etermine the number of hydrogen atoms in the identified molecule.
In the molecule $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{}_{6}$ , the subscript following the H (hydrogen) indicates the number of hydrogen atoms in the molecule. So, there are12 hydrogen atoms in one molecule of $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{}_{6}$ .

STEP 4

Calculate the total number of hydrogen atoms on the right-hand side of the equation.
Since there is only one molecule of $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{}_{6}$ on the right-hand side of the equation, and each molecule contains12 hydrogen atoms, the total number of hydrogen atoms on the right-hand side of the equation is12.
The total number of hydrogen atoms on the right-hand side of the equation is12.

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