Math  /  Algebra

QuestionThe heat of the reaction, ΔHr×n\Delta H_{r \times n}, is found by dividing the qrxnq_{r x n} by the moles of zinc used, nznn_{z n}. ΔHrxn=qrxnnzn\Delta H_{r x n}=\frac{q_{r x n}}{n_{z n}}
What is the ΔHr×n\Delta H_{r \times n} if qr×n=0.332kcalq_{r \times n}=-0.332 \mathrm{kcal} and n=0.0084n=0.0084 moles? a. 40cal/mol40 \mathrm{cal} / \mathrm{mol} b. 40.kcal/mol-40 . \mathrm{kcal} / \mathrm{mol} C. 40kcal/mol40 \mathrm{kcal} / \mathrm{mol}

Studdy Solution
Round the result to match the options provided. The closest option is:
ΔHr×n40kcal/mol\Delta H_{r \times n} \approx -40 \, \text{kcal/mol}
Therefore, the correct answer is:
b. 40kcal/mol-40 \, \text{kcal/mol}

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