Math  /  Calculus

QuestionSimplify the expression: (x+Δx)29(x+Δx)+8(x29x+8)Δx\frac{(x+\Delta x)^{2}-9(x+\Delta x)+8-(x^{2}-9 x+8)}{\Delta x}.

Studdy Solution
Now, we can cancel out Δx\Delta x from the numerator and the denominator.
Δx(2x+Δx9)Δx=2x+Δx9\frac{\Delta x(2x + \Delta x -9)}{\Delta x} =2x + \Delta x -9So, the simplified form of the given expression is 2x+Δx92x + \Delta x -9.

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