Question\begin{align*} \text{Given:} \\ \text{The length of the blue wall is } & 6 \text{ meters,} \\ \text{The width of the blue wall is } & 1.5 \text{ meters,} \\ \text{The length of the floor is } & 6 \text{ meters,} \\ \text{The width of the floor is } & 3 \text{ meters.} \\ \end{align*}

Studdy Solution
Calculate the area of the floor using the formula for the area of a rectangle:
$$\text{Area of Floor} = \text{Length} \times \text{Width}$$
Substitute the given values:
$$= 6 \text{ m} \times 3 \text{ m}$$
$$= 18 \text{ m}^2$$
The area of the blue wall is $9 \text{ m}^2$, and the area of the floor is $18 \text{ m}^2$.