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Math  /  Geometry

Question\begin{align*} \text{Given:} \\ \text{The length of the blue wall is } & 6 \text{ meters,} \\ \text{The width of the blue wall is } & 1.5 \text{ meters,} \\ \text{The length of the floor is } & 6 \text{ meters,} \\ \text{The width of the floor is } & 3 \text{ meters.} \\ \end{align*}

Studdy Solution

STEP 1

1. The blue wall is rectangular.
2. The floor is rectangular.

STEP 2

1. Calculate the area of the blue wall.
2. Calculate the area of the floor.

STEP 3

Calculate the area of the blue wall using the formula for the area of a rectangle:
Area of Blue Wall=Length×Width \text{Area of Blue Wall} = \text{Length} \times \text{Width}
Substitute the given values:
=6 m×1.5 m = 6 \text{ m} \times 1.5 \text{ m}
=9 m2 = 9 \text{ m}^2

STEP 4

Calculate the area of the floor using the formula for the area of a rectangle:
Area of Floor=Length×Width \text{Area of Floor} = \text{Length} \times \text{Width}
Substitute the given values:
=6 m×3 m = 6 \text{ m} \times 3 \text{ m}
=18 m2 = 18 \text{ m}^2
The area of the blue wall is 9 m2 9 \text{ m}^2 , and the area of the floor is 18 m2 18 \text{ m}^2 .

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