Question$\begin{array}{l}\sqrt[3]{2197}= \\ \sqrt[3]{125}= \\ \sqrt[3]{4096}= \\ \sqrt[3]{27}=\end{array}$

Studdy Solution
Identify the cube root of $27$.
Since $3^3 = 3 \times 3 \times 3 = 27$, the cube root of $27$ is:
$\sqrt[3]{27} = 3$
The cube roots are:
$\begin{array}{l} \sqrt[3]{2197} = 13 \\ \sqrt[3]{125} = 5 \\ \sqrt[3]{4096} = 16 \\ \sqrt[3]{27} = 3 \\ \end{array}$