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Math  /  Numbers & Operations

Question21973=1253=40963=273=\begin{array}{l}\sqrt[3]{2197}= \\ \sqrt[3]{125}= \\ \sqrt[3]{4096}= \\ \sqrt[3]{27}=\end{array}

Studdy Solution

STEP 1

1. We are tasked with finding the cube roots of the numbers 21972197, 125125, 40964096, and 2727.
2. The cube root of a number xx is a number yy such that y3=xy^3 = x.

STEP 2

1. Find the cube root of 21972197.
2. Find the cube root of 125125.
3. Find the cube root of 40964096.
4. Find the cube root of 2727.

STEP 3

Identify the cube root of 21972197.
Since 133=13×13×13=219713^3 = 13 \times 13 \times 13 = 2197, the cube root of 21972197 is:
21973=13\sqrt[3]{2197} = 13

STEP 4

Identify the cube root of 125125.
Since 53=5×5×5=1255^3 = 5 \times 5 \times 5 = 125, the cube root of 125125 is:
1253=5\sqrt[3]{125} = 5

STEP 5

Identify the cube root of 40964096.
Since 163=16×16×16=409616^3 = 16 \times 16 \times 16 = 4096, the cube root of 40964096 is:
40963=16\sqrt[3]{4096} = 16

STEP 6

Identify the cube root of 2727.
Since 33=3×3×3=273^3 = 3 \times 3 \times 3 = 27, the cube root of 2727 is:
273=3\sqrt[3]{27} = 3
The cube roots are:
21973=131253=540963=16273=3\begin{array}{l} \sqrt[3]{2197} = 13 \\ \sqrt[3]{125} = 5 \\ \sqrt[3]{4096} = 16 \\ \sqrt[3]{27} = 3 \\ \end{array}

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