Math Statement

Problem 3801

Solve the inequality. Graph the solution. 825(k2)-8 \leq \frac{2}{5}(k-2)
The solution is \square 1.

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Problem 3802

Solve the inequality. Graph the solution. 14(d+1)<2-\frac{1}{4}(d+1)<2
The solution is \square .

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Problem 3803

Given that f(x)=x26xf(x)=x^{2}-6 x and g(x)=x+7g(x)=x+7, find and simplify the following: a. (f+g)(x)=(f+g)(x)= \square and the domain of (f+g)(f+g) is b. (fg)(x)=(f-g)(x)= \square and the domain of (fg)(f-g) is c. (fg)(x)=(f g)(x)= \square and the domain of (fg)(f g) is d. (fg)(x)=\left(\frac{f}{g}\right)(x)= \square and the domain of (fg)\left(\frac{f}{g}\right) is

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Problem 3804

Solve the inequality. Graph the solution. 203.2(c4.3)20 \geq-3.2(c-4.3)
The solution is \square .

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Problem 3805

Given f(x)=10x2+x12f(x)=10 x^{2}+x-12 and g(x)=8x2+3g(x)=8 x^{2}+3, find (fg)(x)(f-g)(x).

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Problem 3806

Given f(x)=x210x+25f(x)=x^{2}-10 x+25 and g(x)=x29x+20g(x)=x^{2}-9 x+20, find (fg)(x)\left(\frac{f}{g}\right)(x) and simplify the resulting function.

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Problem 3807

workld=68561434 Part 2 of 3 3.4.13 Use the following function to answer parts a through c. f(x) = x²+6x² - 182x-187 C po SOF a. List all rational zeros that are possible according to the Rational Zero Theorem. ±1, ±11, ± 17, ± 187 (Type an integer or a simplified fraction. Use a comma to separate answers as needed. Type each ans b. Use synthetic division to test several possible rational zeros in order to identify one actual zero. (Simplify your answer.) One rational zero of the given function is

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Problem 3808

Solve the linear programming problem.  Maximize P=15x+25y Subject to 0.6x+1.2y9000.03x+0.04y360.3x+0.2y300x,y0\begin{aligned} & \text { Maximize } P=15 x+25 y \\ \text { Subject to } \quad 0.6 x+1.2 y & \leq 900 \\ 0.03 x+0.04 y & \leq 36 \\ 0.3 x+0.2 y & \leq 300 \\ x, y & \geq 0 \end{aligned}
What is the maximum value of P ? Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. P=P= \square (Simplify your answer. Type an integer or a fraction.) B. There is no maximum value of PP.

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Problem 3809

f(x)=3x3x23x+2f(x)=\frac{3 x-3}{x^{2}-3 x+2}
Answer Attempt 1 out of 2
Horizontal Asymptote: y=y= \square No horizontal asymptote
Vertical Asymptote: x=x= \square No vertical asymptote xx-Intercept: \square , 0) No xx-intercept \qquad yy-Intercept: (0, \square ) No yy-intercept
Hole: \square \square No hole

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Problem 3810

Inverse of 7mod47 \bmod 4 1-1 3 2 1

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Problem 3811

Simplify the expression. y13y12y14\frac{y^{\frac{1}{3}}}{y^{-\frac{1}{2}} y^{\frac{1}{4}}}
Write your answer using only positive exponents. Assume that all variables are positive real numbers

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Problem 3812

f(x)=x2162x216x+32f(x)=\frac{x^{2}-16}{2 x^{2}-16 x+32}
Answer Attempt 1 out of 2
Horizontal Asymptote: y=y= \square No horizontal asymptote \square No vertical asymptote
Vertical Asymptote: x=x= No vertical asymptote xx-Intercept: \square ,0) \square yy-Intercept: (0, \square No yy-intercept \square Hole: \square \square No hole

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Problem 3813

h(z)=1z+9z2 for z>0h(z)=\frac{1}{z}+9 z^{2} \text { for } z>0
Select the exact global maximum and minimum values of the function. The global maximum of h(z)h(z) on z>0z>0 does not exist, the global minimum is 183+943\sqrt[3]{18}+\sqrt[3]{\frac{9}{4}} The global maximum of h(z)h(z) on z>0z>0 is 19+729\frac{1}{9}+729, the global minimum is 93+943\sqrt[3]{9}+\sqrt[3]{\frac{9}{4}} The global maximum of h(z)h(z) on z>0z>0 is 118+729\frac{1}{18}+729, the global minimum is 183+943\sqrt[3]{18}+\sqrt[3]{\frac{9}{4}} The global maximum of h(z)h(z) on z>0z>0 does not exist, the global minimum is 183+923\sqrt[3]{18}+\sqrt[3]{\frac{9}{2}} The global maximum of h(z)h(z) on z>0z>0 is 118+729\frac{1}{18}+729, the global minimum is 93+943\sqrt[3]{9}+\sqrt[3]{\frac{9}{4}}

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Problem 3814

2+25x+17=35-2+25 x+17=-35

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Problem 3815

Divide using synthetic division. (6x34x2+3x2)÷(x1)(6x34x2+3x2)÷(x1)=\begin{array}{l} \left(6 x^{3}-4 x^{2}+3 x-2\right) \div(x-1) \\ \left(6 x^{3}-4 x^{2}+3 x-2\right) \div(x-1)= \end{array} \square (Simplify your answer. Do not factor.)

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Problem 3816

Minga f(x)=2x+2x21f(x)=\frac{2 x+2}{x^{2}-1}
Answer Attempt 1 out of 2
Horizontal Asymptote: y=y= \square No horizontal asymptote
Vertical Asymptote: x=x= \square No vertical asymptote xx-Intercept: ( \square , 0) No xx-intercept \qquad yy-Intercept: ( 0, \square ) \qquad No yy-intercept
Hole: \square , \square No hole

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Problem 3817

The function f(x)=9x+7x1f(x)=9 x+7 x^{-1} has one local minimum and one local maximum. This function has a local maximum at x=x= \square with value \square and a local minimum at x=x= \square with value \square

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Problem 3818

f(x)=2x+2x21f(x)=\frac{2 x+2}{x^{2}-1}
Answer Attempt 1 out of 2
Horizontal Asymptote: y=y= \square No horizontal asymptote \square Vertical Asymptote: x=x= No vertical asymptote \qquad xx-Intercept: \square ,0) \square No xx-intercept yy-Intercept: (0, \square ) No yy-intercept
Hole: \square , \square No hole \square

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Problem 3819

Question 7
An exponential function f(x)=abxf(x)=a \cdot b^{x} passes through the points (0,7000)(0,7000) and (3,56)(3,56). What are the values of aa and bb ? a=a= \square and b=b= \square

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Problem 3820

Plot all of the existing five features of the following rational function (some may not be needed). If you get a fraction or decimal then plot as close to the true location as possible. f(x)=3x9x22x15f(x)=\frac{-3 x-9}{x^{2}-2 x-15}
Plot Rational Function Vertical Asymptote Horizontal Asymptote x-Intercept y-Intercept Hole

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Problem 3821

Evaluate the following. Click on "Not a real number" if applicable. (a) 3215=-32^{\frac{1}{5}}= \square (b) 3612=-36^{\frac{1}{2}}= \square

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Problem 3822

8. Using a calculator, determine the solutions for each equation, to two decimal places, on the interval 0x2π0 \leq x \leq 2 \pi. a) 3sinx=sinx+13 \sin x=\sin x+1 c) cosx1=cosx\cos x-1=-\cos x b) 5cosx3=3cosx5 \cos x-\sqrt{3}=3 \cos x d) 5sinx+1=3sinx5 \sin x+1=3 \sin x

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Problem 3823

Solve the equation: log2(x1)=3\log _{2}(x-1)=3

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Problem 3824

Listen
Determine if the augmented matrix is in row echelon form. [171033]\left[\begin{array}{cccc} 1 & 7 & \vdots & 1 \\ 0 & 3 & \vdots & -3 \end{array}\right] yes no
If not, use elementary row operations to write it in row echelon form. If the matrix is in row echelon form, then leave this matri) blank. \square \square \square \square \square \square ]] Previous 36 37
38 39 40 41 42 43 44 45 Next Support CaleChat

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Problem 3825

64x23664 x^{2}-36

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Problem 3826

2. Find the domain of the function f(x)=x21x29f(x)=\frac{x^{2}-1}{x^{2}-9}.
Select the correct choice below and, if necessary, fill in the answer box(es) to complete your choice. A. The domain is {x\{x \mid \qquad \}. (Simplify your answer. Type an inequality. Use a comma to separate answers as needed.) B. The domain is {xx\{x \mid x \neq \qquad 3. (Simplify your answer. Use a comma to separate answers as needed.) C. The domain is {xx\{x \mid x \leq \qquad , xx \neq \qquad \}. (Simplify your answer. Use a comma to separate answers as needed.) D. The domain is {xx\{x \mid x \geq \qquad , xx \neq \qquad \}. (Simplify your answer. Use a comma to separate answers as needed.) E. The domain is the set of all real numbers.

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Problem 3827

b) 8x+1=16x28^{x+1}=16^{x-2}

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Problem 3828

Find f(x)f^{\prime}(x). f(x)=(5x6+6)3f(x)=\begin{array}{l} f(x)=\left(5 x^{6}+6\right)^{3} \\ f^{\prime}(x)=\square \end{array}

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Problem 3829

Buscar 5:52 p.m. Dom nov 17 ixl.com
Graph this line: y+2=3(x6)y+2=3(x-6)
Click to select points on the graph. Submit Work it out Practice in the app

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Problem 3830

Solve and reduce the result to lowest fractional terms. Input answer as a fraction, not a decimal. 137÷36=\frac{13}{7} \div \frac{3}{6}=

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Problem 3831

8x+18>22-8 x+18 \mid>-22

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Problem 3832

Buscar ixl.com
Graph this line using the slope and yy-intercept: y=16x+2y=\frac{1}{6} x+2
Click to select points on the graph. Submit

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Problem 3833

(B) The functions jj and kk are given by j(x)=2(sinx)(cosx)cosxk(x)=8e(3x)e\begin{array}{l} j(x)=2(\sin x)(\cos x)-\cos x \\ k(x)=8 e^{(3 x)}-e \end{array} (i) Solve j(x)=0j(x)=0 for values of xx in the interval [0,π2]\left[0, \frac{\pi}{2}\right].

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Problem 3834

Differentiate. y=ln[(x+6)3(x+7)6(x+2)4]ddx[ln[(x+6)3(x+7)6(x+2)4]]=\begin{array}{c} y=\ln \left[(x+6)^{3}(x+7)^{6}(x+2)^{4}\right] \\ \frac{d}{d x}\left[\ln \left[(x+6)^{3}(x+7)^{6}(x+2)^{4}\right]\right]= \end{array}

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Problem 3835

Differentiate the following function. y=(lnx)8+ln(x8)dydx=\begin{array}{l} y=(\ln x)^{8}+\ln \left(x^{8}\right) \\ \frac{d y}{d x}=\square \end{array} \square

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Problem 3836

Given the function g(x)=6x3+18x2144xg(x)=6 x^{3}+18 x^{2}-144 x, find the first derivative, g(x)g^{\prime}(x). g(x)=g^{\prime}(x)= \square Notice that g(x)=0g^{\prime}(x)=0 when x=4x=-4, that is, g(4)=0g^{\prime}(-4)=0. Now, we want to know whether there is a local minimum or local maximum at x=4x=-4, so we will use the second derivative test. Find the second derivative, g(x)g^{\prime \prime}(x). g(x)=g^{\prime \prime}(x)= \square Evaluate g(4)g^{\prime \prime}(-4). g(4)=g^{\prime \prime}(-4)= \square Based on the sign of this number, does this mean the graph of g(x)g(x) is concave up or concave down at x=4x=-4 ? At x=4x=-4 the graph of g(x)g(x) is Select an answer vv Based on the concavity of g(x)g(x) at x=4x=-4, does this mean that there is a local minimum or local maximum at x=4x=-4 ? At x=4x=-4 there is a local Select an answer \checkmark

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Problem 3837

Question 15
Use the properties of logs to condense the expression: 3lnx+2lny4lnz3 \ln x+2 \ln y-4 \ln z

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Problem 3838

We wish to solve the equation 4x310x2+2x+4=04 x^{3}-10 x^{2}+2 x+4=0
This can be rearranged to x=4x3+10x242x=\frac{-4 x^{3}+10 x^{2}-4}{2}
Starting with x0=1x_{0}=1, use the iteration formula xn+1=4(xn)3+10(xn)242x_{n+1}=\frac{-4\left(x_{n}\right)^{3}+10\left(x_{n}\right)^{2}-4}{2} to find the value of x3x_{3}. Give your answer correct to 3 decimal places.

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Problem 3839

Simplify. 61896 \sqrt{189}

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Problem 3840

Write the equation in its equivalent exponential form. 5=log6M5=\log _{6} M

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Problem 3841

Simplify. 7637 \sqrt{63}

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Problem 3842

3843 \sqrt{84}

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Problem 3843

Who did it? limx2x2+2x8x2=\lim _{x \rightarrow 2} \frac{x^{2}+2 x-8}{x-2}=
0 = Selena Gomez 2 = Lebron James 6 = Taylor Swift DNE = Jay Z

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Problem 3844

implify. 499\sqrt{\frac{49}{9}}

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Problem 3845

Solve the following: 84.9226.4=84.92-26.4=

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Problem 3846

t=18\mathrm{t}=18 days? Answer in appropriate units.

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Problem 3847

Evaluate 224x24x2x2y22(x2+y2)dzdydx\int_{-2}^{2} \int_{-\sqrt{4-x^{2}}}^{\sqrt{4-x^{2}}} \int_{\sqrt{x^{2} y^{2}}}^{2}\left(x^{2}+y^{2}\right) d z d y d x

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Problem 3848

2. Let S(t)=11+etS(t)=\frac{1}{1+e^{-t}}. a. Find S(t)S^{\prime}(t). Show your work completely to justify your response. b. Which of the following equations hold true? Explain your thinking fully. (Note: Only one equation is true.) 1) S(t)=S(t)S^{\prime}(t)=S(t) 2) S(t)=(S(f))2S^{\prime}(t)=(S(f))^{2} 3) S(t)=S(t)(1S(t))S^{\prime}(t)=S(t)(1-S(t)) 4) S(t)=S(t)S^{\prime}(t)=-S(-t)
Note: The function S(f)S(f) is called the "Sigmoid activation function" and is extremely important in machine learning and artificial intelligence.

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Problem 3849

Find the zeros for the polynomial function and give the multiplicity for each zero. State whether the graph crosses the x -axis or touches the x-axis and turns around at each zero. f(x)=x3+3x24x12f(x)=x^{3}+3 x^{2}-4 x-12
Determine the zero(s), if they exist. The zero(s) is/are \square . (Type integers or decimals. Use a comma to separate answers as needed.)

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Problem 3850

5. [-/1 Points]
DETAILS MY NOTES TANAPCALC10 6.5.0 Find the average value of the function ff over the interval [4,9][4,9]. f(x)=7xf(x)=7-x \square

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Problem 3851

11 \leftarrow \quad Find dydx\frac{d y}{d x} y=x1t4+5dtdydx=\begin{array}{l} y=\int_{x}^{1} \sqrt{t^{4}+5} d t \\ \frac{d y}{d x}=\square \end{array} \square

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Problem 3852

Simplify. 15135\sqrt{\frac{15}{135}}

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Problem 3853

If n=400\mathrm{n}=400 and pundefined(phat)=0.9\widehat{p}(p-h a t)=0.9, construct a 99%99 \% confidence interval. Give your answers to three decimals \square <p<<p< \square

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Problem 3854

Unit 2 Assi
Convert the following expressions between exponential and logarithmic form. a. 2401=742401=74 [1 mark] b. a=logbc[1a=\log _{b} c[1 mark]

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Problem 3855

Use long division to divide. SEE EXAMPLE 1
15. x3+5x2x5x^{3}+5 x^{2}-x-5 divided by x1x-1
16. 2x3+9x2+10x+32 x^{3}+9 x^{2}+10 x+3 divided by 2x+12 x+1
17. 3x32x2+7x+93 x^{3}-2 x^{2}+7 x+9 divided by x23xx^{2}-3 x
18. 2x46x2+32 x^{4}-6 x^{2}+3 divided by 2x62 x-6

Use synthetic division to divide. SEE EXAMPLE
19. x425x2+144x^{4}-25 x^{2}+144 divided by x4x-4
20. x3+6x2+3x10x^{3}+6 x^{2}+3 x-10 divided by x+5x+5
21. x5+2x43x3+x1x^{5}+2 x^{4}-3 x^{3}+x-1 divided by x+2x+2
22. x4+7x3+x22x12-x^{4}+7 x^{3}+x^{2}-2 x-12 divided by x3x-3

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Problem 3856

In the following problem, divide using long division. State the quotient, q(x)q(x), and the remainder, r(x)r(x). 4x42x2+2xx44x42x2+2xx4=\begin{array}{l} \frac{4 x^{4}-2 x^{2}+2 x}{x-4} \\ \frac{4 x^{4}-2 x^{2}+2 x}{x-4}= \end{array} \square \square +x4+\frac{\square}{x-4} (Simplify your answers. Do not factor. Use integers or fractions for any numbers in the expressions.)

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Problem 3857

Add the following two binomials. (8a14a5)+(14a518a)\left(8 a-14 a^{5}\right)+\left(14 a^{5}-18 a\right)
Submit Question

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Problem 3858

Use a CALCULATOR to complete the homeworkl
1. Select all the equations that have 2 solutions a. (x+3)2=9x+3=\sqrt{(x+3)^{2}}=\sqrt{9} \quad x+3= b. (x5)2=5(x-5)^{2}=-5 c. (x+2)26=0(x+2)^{2}-6=0 d. (x9)2+25=0(x-9)^{2}+25=0 e. (x+10)2=1(x+10)^{2}=1 f. (x8)2=0(x-8)^{2}=0 g. 5=(x+1)(x+1)5=(x+1)(x+1)

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Problem 3859

Solve the equation on the interval 0θ<2π0 \leq \theta<2 \pi. cos(2θπ2)=1\cos \left(2 \theta-\frac{\pi}{2}\right)=-1

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Problem 3860

Divide using long division. State the quotient, q(x)q(x), and the remainder, r(x)r(x). (15x28x7)÷(5x6)(15x28x7)÷(5x6)=+5x6\begin{array}{c} \left(15 x^{2}-8 x-7\right) \div(5 x-6) \\ \left(15 x^{2}-8 x-7\right) \div(5 x-6)=\square+\frac{\square}{5 x-6} \end{array} (Simplify your answers. Do not factor.)

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Problem 3861

Solve the equation. 2sin2θ3sinθ+1=02 \sin ^{2} \theta-3 \sin \theta+1=0

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Problem 3862

a. Use synthetic division to show that 2 is a solution of the polynomial equation below. 13x3+15x210x144=013 x^{3}+15 x^{2}-10 x-144=0 b. Use the solution from part (a) to solve this problem. The number of eggs, f(x)f(x), in a female moth is a function of her abdominal width, in millimeters, modeled by the equation below. f(x)=13x3+15x210x41f(x)=13 x^{3}+15 x^{2}-10 x-41
What is the abdominal width when there are 103 eggs? a. The number 2 is a solution to the equation because the remainder of the division, 13x3+15x210x14413 x^{3}+15 x^{2}-10 x-144 divided by x2x-2, is \square

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Problem 3863

Solve the equation. 2+2sinθ=4cos2θ2+2 \sin \theta=4 \cos ^{2} \theta

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Problem 3864

Use Descartes's Rule of Signs to determine the possible numbers of positive and negative real zeros of f(x)=9x47x34x26x+7f(x)=9 x^{4}-7 x^{3}-4 x^{2}-6 x+7.
What is the possible number of positive real zeros? \square (Use a comma to separate answers as needed.)

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Problem 3865

(3x+1)(3x+3)(3 x+1)(3 x+3)

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Problem 3866

Add the polynomials: (7x56x4+10x8)+(6x46x3+x+8)\left(-7 x^{5}-6 x^{4}+10 x-8\right)+\left(6 x^{4}-6 x^{3}+x+8\right) Submit Question

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Problem 3867

9. 37÷514=-\frac{3}{7} \div \frac{5}{14}= A. 1595\frac{15}{95} B. 1598-\frac{15}{98} C. 1151 \frac{1}{5} (D)
10. Which of the following is in order from shortest to longest? F. 212ft,79yd,223ft,33in2 \frac{1}{2} \mathrm{ft}, \frac{7}{9} \mathrm{yd}, 2 \frac{2}{3} \mathrm{ft}, 33 \mathrm{in}. G. 79yd,212ft,223ft,33in\frac{7}{9} \mathrm{yd}, 2 \frac{1}{2} \mathrm{ft}, 2 \frac{2}{3} \mathrm{ft}, 33 \mathrm{in}. H. 79yd,212ft,33in.,223ft\frac{7}{9} \mathrm{yd}, 2 \frac{1}{2} \mathrm{ft}, 33 \mathrm{in} ., 2 \frac{2}{3} \mathrm{ft} (J.) 33 in ., 212ft,223ft,79yd2 \frac{1}{2} \mathrm{ft}, 2 \frac{2}{3} \mathrm{ft}, \frac{7}{9} \mathrm{yd}

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Problem 3868

Solve and round the FINAL answer to two decimal places. (1.18+9.10)×(8.521.26)=(1.18+9.10) \times(8.52-1.26)=

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Problem 3869

x3+2x2+15x5x+3\frac{x^{3}+2 x^{2}+15 x-5}{x+3}

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Problem 3870

51) log48log42x=log446\log _{4} 8-\log _{4} 2 x=\log _{4} 46

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Problem 3871

yˉ=1m2yρ(x,y)dA=x32801022x(4y+10xy+3y2)dydx=32801[4y22+10xy22+3y33]y=0y=22xdx=11401(2430x12x2+]01==114[1]\begin{aligned} \bar{y} & =\frac{1}{m} \iint^{2} y \rho(x, y) d A \\ & =\frac{x^{3}}{28} \int_{0}^{1} \int_{0}^{2-2 x}\left(4 y+10 x y+3 y^{2}\right) d y d x \\ & =\frac{3}{28} \int_{0}^{1}\left[\frac{4 y^{2}}{2}+\frac{10 x y^{2}}{2}+\frac{3 y^{3}}{3}\right]_{y=0}^{y=2-2 x} d x \\ & =\frac{1}{14} \int_{0}^{1}\left(24-30 x-12 x^{2}+\square\right]_{0}^{1}=\square \\ & =\frac{1}{14}[1]\end{aligned}

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Problem 3872

Find the mass and the center of mass of the solid EE with the given density function ρ(x,y,z)\rho(x, y, z). EE lies under the plane z=1+x+yz=1+x+y and above the region in the xyx y-plane bounded by the curves y=x,y=0y=\sqrt{x}, y=0, and x=1;ρ(x,y,z)=8x=1 ; \rho(x, y, z)=8. m=158/15m=158 / 15

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Problem 3873

(1 point)
Differentiate y=1x2sin1xy=\sqrt{1-x^{2}} \sin ^{-1} x y=y^{\prime}=

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Problem 3874

Solve the following inequality algebraically. x211<x5x^{2}-11<x-5
Answer Attempt 1 out of 2

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Problem 3875

Find ff^{\prime}, given f(x)=1,f(x)=xsin3(x2)x5+1f^{\prime}(x)=1, f(x)=\frac{x \sin ^{3}\left(x^{2}\right)}{\sqrt{x^{5}+1}}

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Problem 3876

Solve the system graphically. (If there is no solution, enter NO SOLUTION.) {x+y=8x22x80+y2=0\left\{\begin{array}{r} -x+y=8 \\ x^{2}-2 x-80+y^{2}=0 \end{array}\right. (smaller xx-value) (x,y)(1)(x, y)(1)  (larger x-value) (x,y)()\text { (larger } x \text {-value) } \quad(x, y)(\square)

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Problem 3877

Solve the system graphically. (If there is no solution, enter NO SOLUTION.) {x2+y2=17(x7)2+y2=10\left\{\begin{array}{r} x^{2}+y^{2}=17 \\ (x-7)^{2}+y^{2}=10 \end{array}\right. (smaller yy-value) (x,y)(\quad(x, y)( \square ) (larger yy-value) (x,y)((x, y)( \square )

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Problem 3878

4b Complete the short division to find 995.6÷2995.6 \div 2

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Problem 3879

stion list
Sublyact and check the following 171917-19
2uestion 1 - 17 19 -2 (Type an integer a decimal.)
Question 2
Question 3
Question 4

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Problem 3880

Consider the curve given by the equation (2y+1)324x=3.3(2y(2 y+1)^{3}-24 x=-3 . \quad 3(2 y (a) Show that dydx=4(2y+1)2\frac{d y}{d x}=\frac{4}{(2 y+1)^{2}}. (b) Write an equation for the line tangent to the curve at the point (1,2)(-1,-2) (c) Evaluate d2ydz2\frac{d^{2} y}{d z^{2}} at the point (1,2)(-1,-2). (d) The point (16,0)\left(\frac{1}{6}, 0\right) is on the curve. Find the value of (y1)(0)\left(y^{-1}\right)^{\prime}(0).

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Problem 3881

Given the matrix A=[672074004]A=\left[\begin{array}{ccc}6 & -7 & 2 \\ 0 & -7 & -4 \\ 0 & 0 & 4\end{array}\right], what are the eigenvalues?
Enter each eigenvalue separated by a SEMICOLON. (eg. 4; 1; 6).

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Problem 3882

Establish the identity. secθ+tanθtanθsecθ+tanθsecθ=cosθcotθ\frac{\sec \theta+\tan \theta}{\tan \theta}-\frac{\sec \theta+\tan \theta}{\sec \theta}=\cos \theta \cot \theta

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Problem 3883

b) (12)3=(2)\left(-\frac{1}{2}\right)^{-3}=(-2)

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Problem 3884

Simplify the expression: 6x12x+1xx1+1x+1=\frac{\frac{6}{x-1}-\frac{2}{x+1}}{\frac{x}{x-1}+\frac{1}{x+1}}=

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Problem 3885

Solve the system graphically or algebraically. (If there is no solu {x2+y=5exy=0\left\{\begin{array}{l} x^{2}+y=5 \\ e^{x}-y=0 \end{array}\right. smaller xx-value (x,y)=(L(x, y)=(L \square larger xx-value (x,y)=()(x, y)=() \square Explain your choice of

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Problem 3886

2W2 W Mark for Review 4%4 \%
Consider the curve in the xyx y-plane defined by x2y25=1x^{2}-\frac{y^{2}}{5}=1. It is known that dydx=5xy\frac{d y}{d x}=\frac{5 x}{y} and d2ydx2=25y3\frac{d^{2} y}{d x^{2}}=-\frac{25}{y^{3}}. Which of the following statements is true about the curve in Quadrant IV? A) The curve is concave up because dydx>0\frac{d y}{d x}>0.
B The curve is concave down because dydx<0\frac{d y}{d x}<0.
C The curve is concave up because d2ydx2>0\frac{d^{2} y}{d x^{2}}>0.
D The curve is concave down because d2ydx2<0\frac{d^{2} y}{d x^{2}}<0.

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Problem 3887

Complete the short division to find 507.2÷8507.2 \div 8

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Problem 3888

Simplify the following expression. Assume any factors you cancel are not zero. 24+24a+4a224+32a=\frac{24+\frac{24}{a}+\frac{4}{a^{2}}}{24+\frac{32}{a}}= \square \square

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Problem 3889

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8. [0.9/1.35 Points]

DETAILS MY NOTES CRAUDCOLALG6 4.5.EX.006. PREVIOUS ANSWERS PRACTICE ANOTHER
Suppose you have a balance of BB dollars on a credit card. You choose to stop charging and pay off the card, making only minimum monthly payments. If your card charges an APR of rr, as a decimal, and requires a minimum monthly payment of 5%5 \% of the balance, then the time TT, in months, required to reduce your balance to $100\$ 100 is given by T=2log(B)log(0.95(1+r12))T=\frac{2-\log (B)}{\log \left(0.95\left(1+\frac{r}{12}\right)\right)}
Suppose your current balance is $8000\$ 8000. (a) How long will it take to reduce your balance to $100\$ 100 if the APR for your card is 29%29 \% ? Report your answer to the nearest whole month. \qquad 143143 xx months (b) Plot the graph of TT versus rr. Use a horizontal span of 0 to 0.3 . TT TT

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Problem 3890

Solve: ((295×6)÷5)+48=?((295 \times 6) \div 5)+48=?

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Problem 3891

the functions f(x)=2x+3f(x)=\frac{2}{x+3} and g(x)=11x+2g(x)=\frac{11}{x+2}, find the compositio tation. (fg)(x)=(f \circ g)(x)= \square
Domain of fgf \circ g : \square

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Problem 3892

Find the general antiderivative, F(x)F(x), of the function f(x)=45x9910x10+x7f(x)=\frac{4}{5} x^{9}-\frac{9}{10} x^{10}+x^{7} F(x)=F(x)=

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Problem 3893

where CC is an arbitrary constant.
Find the general antiderivative, F(x)F(x), of the function f(x)=6x7246x107+8f(x)=-\frac{6 \sqrt[2]{x^{7}}}{4}-\frac{6 x^{10}}{7}+8 F(x)=F(x)= \square

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Problem 3894

13. Modélise ces polynômes. a) x2+x1x^{2}+x-1 b) 3x+23 x+2 c) 2x-2 x
4. Représente ces polynômes par un modèle. a) x2+3-x^{2}+3 b) 2x23x2 x^{2}-3 x c) 8

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Problem 3895

Find the general antiderivative, F(x)F(x), of the function f(x)=2x464x5f(x)=\frac{2}{x^{4}}-6-\frac{4}{x^{5}} F(x)=F(x)=

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Problem 3896

Find the most general antiderivative by evaluating the following indefinite integral: (3x2+2x+2)dx=\int\left(3 x^{2}+2 x+2\right) d x=\square

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Problem 3897

f(x)={x+24<x<5x+35x<6f(5)=\begin{array}{l}f(x)=\left\{\begin{array}{ll}x+2 & 4<x<5 \\ x+3 & 5 \leqslant x<6\end{array}\right. \\ f(5)=\end{array}

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Problem 3898

Verify using the indicated test that the infinite series converges. (Hint: Use partial fractions.) n=11n(n+1)\sum_{n=1}^{\infty} \frac{1}{n(n+1)}
By the telescoping series test, we have n=11n(n+1)=limn\sum_{n=1}^{\infty} \frac{1}{n(n+1)}=\lim _{n \rightarrow \infty} \square ) == \square , and thus the series converges.

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Problem 3899

Evaluate the expression given below. (0.9)2(0.9)^{2} A. 2.9 B. 0.729 C. 0.81 D. 1.8

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Problem 3900

Find the most general antiderivative by evaluating the following indefinite integral: 6xdx=\int \frac{6}{x} d x= \square
NOTE: The general antiderivative should contain an arbitrary constant.

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