Given that f(x)=x2−6x and g(x)=x+7, find and simplify the following:
a. (f+g)(x)=□ and the domain of (f+g) is
b. (f−g)(x)=□ and the domain of (f−g) is
c. (fg)(x)=□ and the domain of (fg) is
d. (gf)(x)=□ and the domain of (gf) is
workld=68561434
Part 2 of 3
3.4.13
Use the following function to answer parts a through c.
f(x) = x²+6x² - 182x-187
C
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a. List all rational zeros that are possible according to the Rational Zero Theorem.
±1, ±11, ± 17, ± 187
(Type an integer or a simplified fraction. Use a comma to separate answers as needed. Type each ans
b. Use synthetic division to test several possible rational zeros in order to identify one actual zero.
(Simplify your answer.)
One rational zero of the given function is
Solve the linear programming problem.
Subject to 0.6x+1.2y0.03x+0.04y0.3x+0.2yx,y Maximize P=15x+25y≤900≤36≤300≥0 What is the maximum value of P ? Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. P=□ (Simplify your answer. Type an integer or a fraction.)
B. There is no maximum value of P.
f(x)=x2−3x+23x−3 Answer Attempt 1 out of 2 Horizontal Asymptote: y=□
No horizontal asymptote Vertical Asymptote: x=□ No vertical asymptote
x-Intercept: □ , 0) No x-intercept
y-Intercept: (0, □ ) No y-intercept Hole: □□
No hole
h(z)=z1+9z2 for z>0 Select the exact global maximum and minimum values of the function.
The global maximum of h(z) on z>0 does not exist, the global minimum is 318+349
The global maximum of h(z) on z>0 is 91+729, the global minimum is 39+349
The global maximum of h(z) on z>0 is 181+729, the global minimum is 318+349
The global maximum of h(z) on z>0 does not exist, the global minimum is 318+329
The global maximum of h(z) on z>0 is 181+729, the global minimum is 39+349
Minga
f(x)=x2−12x+2 Answer Attempt 1 out of 2 Horizontal Asymptote: y=□ No horizontal asymptote Vertical Asymptote: x=□ No vertical asymptote
x-Intercept: ( □ , 0) No x-intercept
y-Intercept: ( 0, □ ) No y-intercept Hole: □ , □
No hole
The function f(x)=9x+7x−1 has one local minimum and one local maximum. This function has a local maximum at x=□
with value □
and a local minimum at x=□
with value □
Plot all of the existing five features of the following rational function (some may not be needed). If you get a fraction or decimal then plot as close to the true location as possible.
f(x)=x2−2x−15−3x−9 Plot Rational Function
Vertical Asymptote
Horizontal Asymptote
x-Intercept
y-Intercept
Hole
8. Using a calculator, determine the solutions for each equation, to two decimal places, on the interval 0≤x≤2π.
a) 3sinx=sinx+1
c) cosx−1=−cosx
b) 5cosx−3=3cosx
d) 5sinx+1=3sinx
Listen Determine if the augmented matrix is in row echelon form.
⎣⎡1073⋮⋮1−3⎦⎤
yes
no If not, use elementary row operations to write it in row echelon form. If the matrix is in row echelon form, then leave this matri) blank.
□□□□□□]
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2. Find the domain of the function f(x)=x2−9x2−1. Select the correct choice below and, if necessary, fill in the answer box(es) to complete your choice.
A. The domain is {x∣ \}.
(Simplify your answer. Type an inequality. Use a comma to separate answers as needed.)
B. The domain is {x∣x= 3.
(Simplify your answer. Use a comma to separate answers as needed.)
C. The domain is {x∣x≤ , x= \}.
(Simplify your answer. Use a comma to separate answers as needed.)
D. The domain is {x∣x≥ , x= \}.
(Simplify your answer. Use a comma to separate answers as needed.)
E. The domain is the set of all real numbers.
Given the function g(x)=6x3+18x2−144x, find the first derivative, g′(x).
g′(x)=□
Notice that g′(x)=0 when x=−4, that is, g′(−4)=0.
Now, we want to know whether there is a local minimum or local maximum at x=−4, so we will use the second derivative test.
Find the second derivative, g′′(x).
g′′(x)=□
Evaluate g′′(−4).
g′′(−4)=□
Based on the sign of this number, does this mean the graph of g(x) is concave up or concave down at x=−4 ?
At x=−4 the graph of g(x) is Select an answer v
Based on the concavity of g(x) at x=−4, does this mean that there is a local minimum or local maximum at x=−4 ?
At x=−4 there is a local Select an answer ✓
We wish to solve the equation
4x3−10x2+2x+4=0 This can be rearranged to
x=2−4x3+10x2−4 Starting with x0=1, use the iteration formula
xn+1=2−4(xn)3+10(xn)2−4
to find the value of x3.
Give your answer correct to 3 decimal places.
2. Let S(t)=1+e−t1.
a. Find S′(t). Show your work completely to justify your response.
b. Which of the following equations hold true? Explain your thinking fully. (Note: Only one equation is true.)
1) S′(t)=S(t)
2) S′(t)=(S(f))2
3) S′(t)=S(t)(1−S(t))
4) S′(t)=−S(−t) Note: The function S(f) is called the "Sigmoid activation function" and is extremely important in machine learning and artificial intelligence.
Find the zeros for the polynomial function and give the multiplicity for each zero. State whether the graph crosses the x -axis or touches the x-axis and turns around at each zero.
f(x)=x3+3x2−4x−12 Determine the zero(s), if they exist.
The zero(s) is/are □ .
(Type integers or decimals. Use a comma to separate answers as needed.)
Use long division to divide. SEE EXAMPLE 1 15. x3+5x2−x−5 divided by x−1 16. 2x3+9x2+10x+3 divided by 2x+1 17. 3x3−2x2+7x+9 divided by x2−3x 18. 2x4−6x2+3 divided by 2x−6 Use synthetic division to divide. SEE EXAMPLE 19. x4−25x2+144 divided by x−4 20. x3+6x2+3x−10 divided by x+5 21. x5+2x4−3x3+x−1 divided by x+2 22. −x4+7x3+x2−2x−12 divided by x−3
In the following problem, divide using long division. State the quotient, q(x), and the remainder, r(x).
x−44x4−2x2+2xx−44x4−2x2+2x=□□+x−4□
(Simplify your answers. Do not factor. Use integers or fractions for any numbers in the expressions.)
Use a CALCULATOR to complete the homeworkl 1. Select all the equations that have 2 solutions
a. (x+3)2=9x+3=
b. (x−5)2=−5
c. (x+2)2−6=0
d. (x−9)2+25=0
e. (x+10)2=1
f. (x−8)2=0
g. 5=(x+1)(x+1)
Divide using long division. State the quotient, q(x), and the remainder, r(x).
(15x2−8x−7)÷(5x−6)(15x2−8x−7)÷(5x−6)=□+5x−6□
(Simplify your answers. Do not factor.)
a. Use synthetic division to show that 2 is a solution of the polynomial equation below.
13x3+15x2−10x−144=0
b. Use the solution from part (a) to solve this problem. The number of eggs, f(x), in a female moth is a function of her abdominal width, in millimeters, modeled by the equation below.
f(x)=13x3+15x2−10x−41 What is the abdominal width when there are 103 eggs?
a. The number 2 is a solution to the equation because the remainder of the division, 13x3+15x2−10x−144 divided by x−2, is □
Use Descartes's Rule of Signs to determine the possible numbers of positive and negative real zeros of f(x)=9x4−7x3−4x2−6x+7. What is the possible number of positive real zeros?
□ (Use a comma to separate answers as needed.)
9. −73÷145=
A. 9515
B. −9815
C. 151
(D) 10. Which of the following is in order from shortest to longest?
F. 221ft,97yd,232ft,33in.
G. 97yd,221ft,232ft,33in.
H. 97yd,221ft,33in.,232ft
(J.) 33 in ., 221ft,232ft,97yd
Find the mass and the center of mass of the solid E with the given density function ρ(x,y,z).
E lies under the plane z=1+x+y and above the region in the xy-plane bounded by the curves y=x,y=0, and x=1;ρ(x,y,z)=8.
m=158/15
Solve the system graphically. (If there is no solution, enter NO SOLUTION.)
{x2+y2=17(x−7)2+y2=10
(smaller y-value) (x,y)(□ )
(larger y-value) (x,y)(□ )
Consider the curve given by the equation (2y+1)3−24x=−3.3(2y
(a) Show that dxdy=(2y+1)24.
(b) Write an equation for the line tangent to the curve at the point (−1,−2)
(c) Evaluate dz2d2y at the point (−1,−2).
(d) The point (61,0) is on the curve. Find the value of (y−1)′(0).
Solve the system graphically or algebraically. (If there is no solu
{x2+y=5ex−y=0
smaller x-value (x,y)=(L□
larger x-value (x,y)=()□
Explain your choice of
2W Mark for Review
4% Consider the curve in the xy-plane defined by x2−5y2=1. It is known that dxdy=y5x and dx2d2y=−y325.
Which of the following statements is true about the curve in Quadrant IV?
A) The curve is concave up because dxdy>0. B The curve is concave down because dxdy<0. C The curve is concave up because dx2d2y>0. D The curve is concave down because dx2d2y<0.
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CRAUDCOLALG6 4.5.EX.006.
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PRACTICE ANOTHER Suppose you have a balance of B dollars on a credit card. You choose to stop charging and pay off the card, making only minimum monthly payments. If your card charges an APR of r, as a decimal, and requires a minimum monthly payment of 5% of the balance, then the time T, in months, required to reduce your balance to $100 is given by
T=log(0.95(1+12r))2−log(B) Suppose your current balance is $8000.
(a) How long will it take to reduce your balance to $100 if the APR for your card is 29% ? Report your answer to the nearest whole month.
143x months
(b) Plot the graph of T versus r. Use a horizontal span of 0 to 0.3 .
TT
Verify using the indicated test that the infinite series converges. (Hint: Use partial fractions.)
n=1∑∞n(n+1)1 By the telescoping series test, we have ∑n=1∞n(n+1)1=limn→∞□ ) =□ , and thus the series converges.
Find the most general antiderivative by evaluating the following indefinite integral:
∫x6dx=□ NOTE: The general antiderivative should contain an arbitrary constant.