QuestionCalculate the weight of the water molecule $\mathrm{H}_{2} \mathrm{O}$ using atomic weights: $\mathrm{H} = 1.008$, $\mathrm{O} = 15.999$. Round to nearest whole number.

Studdy Solution
Apply the rounding rule to the weight of the water molecule.
Since the decimal part of18.015 is .015, which is less than .5, we round down to the nearest whole number.
So, the weight of the water molecule rounded to the nearest whole number is18.
The weight of the water molecule is18.