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QuestionCalculate the weight of the water molecule H2O\mathrm{H}_{2} \mathrm{O} using atomic weights: H=1.008\mathrm{H} = 1.008, O=15.999\mathrm{O} = 15.999. Round to nearest whole number.

Studdy Solution

STEP 1

Assumptions1. The water molecule is made up of two atoms of hydrogen (H) and one atom of oxygen (). . The atomic weight of hydrogen (H) is1.008.
3. The atomic weight of oxygen () is15.999.

STEP 2

The weight of a molecule is the sum of the atomic weights of all its constituent atoms. For water, this would be the sum of the atomic weights of two hydrogen atoms and one oxygen atom.
WeightH2=2×WeightH+WeightWeight_{H_{2}} =2 \times Weight_{H} + Weight_{}

STEP 3

Now, plug in the given values for the atomic weights of hydrogen and oxygen to calculate the weight of the water molecule.
WeightH2=2×1.008+15.999Weight_{H_{2}} =2 \times1.008 +15.999

STEP 4

Calculate the weight of the water molecule.
WeightH2=2×1.008+15.999=18.015Weight_{H_{2}} =2 \times1.008 +15.999 =18.015

STEP 5

Now that we have the weight of the water molecule, we need to round this weight to the nearest whole number.
The general rule for rounding is- If the number you are rounding is followed by5 or more, round up to the next whole number. - If the number you are rounding is followed by4 or less, round down to the previous whole number.

STEP 6

Apply the rounding rule to the weight of the water molecule.
Since the decimal part of18.015 is .015, which is less than .5, we round down to the nearest whole number.
So, the weight of the water molecule rounded to the nearest whole number is18.
The weight of the water molecule is18.

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