Math  /  Trigonometry

Question5) cosθsecθsinθcotθ=cosθcotθtanθcscθ\frac{\cos \theta}{\sec \theta}-\frac{\sin \theta}{\cot \theta}=\frac{\cos \theta \cot \theta-\tan \theta}{\csc \theta}

Studdy Solution
Compare the simplified LHS and RHS:
Both sides simplify to:
cos2θsin2θ\cos^2 \theta - \sin^2 \theta
Since the simplified LHS and RHS are equal, the identity is verified.
The identity is verified as true.

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