Math  /  Trigonometry

Question5) cosθsecθsinθcotθ=cosθcotθtanθcscθ\frac{\cos \theta}{\sec \theta}-\frac{\sin \theta}{\cot \theta}=\frac{\cos \theta \cot \theta-\tan \theta}{\csc \theta}

Studdy Solution

STEP 1

1. We are given a trigonometric identity to verify.
2. We need to simplify both sides of the equation to show they are equal.
3. We will use trigonometric identities to simplify expressions.

STEP 2

1. Simplify the left-hand side (LHS) of the equation.
2. Simplify the right-hand side (RHS) of the equation.
3. Compare the simplified LHS and RHS to verify the identity.

STEP 3

Simplify the left-hand side (LHS) of the equation:
The LHS is:
cosθsecθsinθcotθ\frac{\cos \theta}{\sec \theta} - \frac{\sin \theta}{\cot \theta}
Recall the identities: secθ=1cosθ\sec \theta = \frac{1}{\cos \theta} and cotθ=cosθsinθ\cot \theta = \frac{\cos \theta}{\sin \theta}.
Substitute these into the LHS:
cosθ1cosθsinθcosθsinθ\frac{\cos \theta}{\frac{1}{\cos \theta}} - \frac{\sin \theta}{\frac{\cos \theta}{\sin \theta}}
Simplify each term:
cos2θsin2θ\cos^2 \theta - \sin^2 \theta

STEP 4

Simplify the right-hand side (RHS) of the equation:
The RHS is:
cosθcotθtanθcscθ\frac{\cos \theta \cot \theta - \tan \theta}{\csc \theta}
Recall the identities: cotθ=cosθsinθ\cot \theta = \frac{\cos \theta}{\sin \theta}, tanθ=sinθcosθ\tan \theta = \frac{\sin \theta}{\cos \theta}, and cscθ=1sinθ\csc \theta = \frac{1}{\sin \theta}.
Substitute these into the RHS:
cosθcosθsinθsinθcosθ1sinθ\frac{\cos \theta \cdot \frac{\cos \theta}{\sin \theta} - \frac{\sin \theta}{\cos \theta}}{\frac{1}{\sin \theta}}
Simplify each term:
cos2θsinθsinθcosθ1sinθ\frac{\frac{\cos^2 \theta}{\sin \theta} - \frac{\sin \theta}{\cos \theta}}{\frac{1}{\sin \theta}}
Multiply by the reciprocal:
cos2θsin2θ\cos^2 \theta - \sin^2 \theta

STEP 5

Compare the simplified LHS and RHS:
Both sides simplify to:
cos2θsin2θ\cos^2 \theta - \sin^2 \theta
Since the simplified LHS and RHS are equal, the identity is verified.
The identity is verified as true.

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