Math  /  Algebra

QuestionSolve for zz in the equation: 3(2z10)=303(2 z-10)=30.

Studdy Solution
Finally, we divide both sides of the equation by6 to solve for zz.
6z6=606\frac{6z}{6} = \frac{60}{6}becomesz=10z =10So, the solution to the equation 3(2z10)=303(2 z-10)=30 is z=10z =10.

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