QuestionSolve for $z$ in the equation: $3(2 z-10)=30$ .

Studdy Solution

STEP 1

Assumptions1. The equation is $3( z-10)=30$ . We are solving for the variable $z$

STEP 2

First, we need to distribute the on the left side of the equation.
$(2 z-10)=30$ becomes $6z -30 =30$

STEP 3

Next, we add30 to both sides of the equation to isolate the term with $z$ on one side.
$6z -30 +30 =30 +30$ becomes $6z =60$

STEP 4

Finally, we divide both sides of the equation by6 to solve for $z$ .
$\frac{6z}{6} = \frac{60}{6}$ becomes $z =10$ So, the solution to the equation $3(2 z-10)=30$ is $z =10$ .

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