Math

QuestionAnalyze your friend's work to find the error in balancing the equation 16÷8=16÷8116 \div 8=16 \div 8-1.

Studdy Solution

STEP 1

Assumptions
1. The original unbalanced equation is 16÷8=16÷8116 \div 8 = 16 \div 8 - 1.
2. The friend's attempt at balancing the equation is 16÷8+1=16÷8116 \div 8 + 1 = 16 \div 8 - 1.
3. We need to identify the error made in the attempt to balance the equation.

STEP 2

Examine the original unbalanced equation.
16÷8=16÷8116 \div 8 = 16 \div 8 - 1

STEP 3

Evaluate both sides of the original unbalanced equation separately.
Left-hand side (LHS):
16÷8=216 \div 8 = 2
Right-hand side (RHS):
16÷81=21=116 \div 8 - 1 = 2 - 1 = 1

STEP 4

Compare the results from STEP_3.
The LHS equals 2, and the RHS equals 1, which confirms that the original equation is indeed unbalanced.

STEP 5

Examine the friend's attempt at balancing the equation.
16÷8+1=16÷8116 \div 8 + 1 = 16 \div 8 - 1

STEP 6

Evaluate both sides of the friend's balanced equation separately.
New Left-hand side (LHS):
16÷8+1=2+1=316 \div 8 + 1 = 2 + 1 = 3
New Right-hand side (RHS):
16÷81=21=116 \div 8 - 1 = 2 - 1 = 1

STEP 7

Compare the results from STEP_6.
The new LHS equals 3, and the new RHS equals 1, which shows that the friend's attempt did not balance the equation.

STEP 8

Identify the error made by the friend.
The friend added 1 to the left side of the original unbalanced equation, which did not correct the imbalance. The correct action would have been to either add 1 to the right side of the original equation or subtract 1 from the left side to maintain equality.

STEP 9

Choose the correct option based on the error identified in STEP_8.
The friend made the error of adding 1 to the left side of the equation.
The correct answer is: C. He added 1 to the left side.

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord